A flexible cable suspended between two vertical supports is hanging under its own weight. The weight of a horizontal roadbed is distributed evenly along the x-axis with the density p = 1.5 Ib/ft. The coordinate system is chosen so that the y-axis passes through the lowest point P and the x-axis is a = 2 ft below P1. If the absolute value of tension force in the cable at point P is T = 2, then the initial value problem that governs the shape of the cable is (Use the notation dy/d for the first derivative) d'y 0.75 sqrt [1+(dy/dx)^2] zp y(0) = 2 2 (0) = The solution of this problem is y = y(x), where y(x) = 4/3cosh (0.75)x+1/2

Q: scuba descends 30 feet then ascends 12 feet before descending another 3 feet. Where is the scuba…

A:

Q: Please show all steps and explain!

A: According to our guidelines we can answer only three subparts, or first question and rest can be…

Q: Number 9 was not answered. I ask for 5 and 9 not 5 and 6. Thank you.

A: We find linear function using table and then find f(0).

Q: tep 2 is cut off. Please resend.

A: note: previous answer was also correct but i think you could not horizontal scroll so I will rewrite…

Q: Please have someone else check if this answer is right

A: The area of the washer is equal to the area of the outer disk minus the area of the inner disk.…

Q: ind the number of 4 letter words with or without meaning, which can be ormed out of the letters of…

A:

Q: Please allof them.Thanks

A: 1) The mean is calculated as follows: x¯=20+11+20+11+165=785=15.6

Q: I asked 5 questions tonight and this is the first one that I for a correct answer.

A: If an object is moving from x=a to x=b, then the work done by the force F is calculated by the…