A flat rectangular piece of cardboard of dimensions 6 cm by 10 cm is transformed into an open-top box by cutting equal-area squares from each of its four corners and folding along lines where the cuts were made. (A picture is included below.) For example, cutting squares of size 1 cm by 1 cm, would yield a box of height • ! cm with a base of dimension 4 cr: by 8 cm. Use calculu. to determine the maximum volume of such an
A flat rectangular piece of cardboard of dimensions 6 cm by 10 cm is transformed into an open-top box by cutting equal-area squares from each of its four corners and folding along lines where the cuts were made. (A picture is included below.) For example, cutting squares of size 1 cm by 1 cm, would yield a box of height • ! cm with a base of dimension 4 cr: by 8 cm. Use calculu. to determine the maximum volume of such an
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2. A flat rectangular piece of cardboard of dimensions 6 cm by 10 cm is transformed into an open-top box by cutting equal-area squares from each of its four corners and folding along lines where the cuts were made.
(A picture is included below.) For example, cutting squares of size 1 cm by 1 cm, would yield a box of height
• ! cm with a base of dimension 4 cr: by 8 cm. Use calculu. to determine the maximum volume of such an
Transcribed Image Text:15 PM Thu Dec 1
5
2. A flat rectangular piece of cardboard of dimensions 6 cm by 10 cm is transformed into an open-top box by
cutting equal-area squares from each of its four corners and folding along lines where the cuts were made.
(A picture is included below.) For example, cutting squares of size 1 cm by 1 cm, would yield a box of height
1 cm with a base of dimension 4 cm by 8 cm. Use calculus to determine the maximum volume of such an
- 10
open-top box that can result.
6
X
X
الدم ١٨ )
x
x
тод
Objective Lunction: Volume = l.w.n
6
16--
x
x
O find constrain ezation and objective function.
x
x
;
***2
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