A five-plot irrigation area has a slope of 0.5:4 (V: H) receives 189m3 of water diverted from the source. The crop factor is known to be 5, and the pan evaporation has a value of 10mm. From the record of PAGASA, the average annual precipitation in the area is 78mm. Calculate the FIR value in mm if the type of soil of the irrigation area is heavy clay and the water delivered is 13m3 per plot.

A five-plot irrigation area has a slope of 0.5:4 (V: H) receives 189m3 of water diverted from the source. The crop factor is known to be 5, and the pan evaporation has a value of 10mm. From the record of PAGASA, the average annual precipitation in the area is 78mm. Calculate the FIR value in mm if the type of soil of the irrigation area is heavy clay and the water delivered is 13m3 per plot.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Compute the average outflow from a 550 hectare river for 15 days period during which the river level dropped half a meter despite an average upstream inflow of 200000m^3/day.During the period, the total seepage loss was 2cm,the total precipitation was 15cm, the total evaporation was 4 cm. Answer must be in cm.
Subject: hydrology for civil engineering Note: need it asap
A lake of surface area 500 Acres received a daily average rainfall equals to Your Roll No (R) mm for a whole month. Direct inflows to this lake during this month were; R, 2R, 1.5R and 3R (in cusecs). Daily evaporation loss during this month was 1R cm/day. Later it was found that the rain gauge was inclined at an angle of 10 degree with the vertical. Direct outflow during this month was 0.25R cusecs/day. Assume the sides of the lake as vertical with initial water depth of 100ft at start of the month. Find the final storage of the lake at the end of the month. Also find the change in storage of the lake and rate of change of storage? Find Your answers in Acre-ft and Acre-ft/month, respectively NOTE: Here R=20
Problem 11.6: The following crops will be cultivated with the indicated areal percentages; cotton (30%), corn (30%), and wheat (40%). The area lies at 36°N latitude. No precipitation is observed in July. Maximum groundwater table elevation is 1.2 m below the ground surface after each irrigation. The minimum readily available moisture in the root zone is estimated to be 60 mm. Taking D-9 m and t-28°C, determine the value of L. Assume that wheat has the same crop coefficient as corn. Take K=1 m/day, μ-0.10, d-2 m, h-0.4 m, ro-0.1 m. Answer: L-66 m
Do it step by step
Q1. A catchment area of 2000 hectares received 10 cm of rainfall in a month. At the outlet of the catchment draining 1.296 million m/day and receive the inflow 0.864 million m/day . the losses due to seepage 1.8 cm and the change in storage 15 million m ,estimate the evaporation in that month?
Example Problem Water budget for a lake provides following observations: Precipitation, P = = 43 in./yr. Evaporation, E = 53 in./yr. Inflow to Lake, Qin = 1 in./yr. Outflow from Lake, Qout = 173 in./yr. Change in Lake storage, AS = -2 in./yr. Find the net groundwater flow. Solution: E SWIn GWin PPT Evap SW Out GWout
Recorded annual maximum 24-hour rainfall magnitudes at stations KTX are as under : YEAR RAINFALL (cm) 1960 12.0 1961 6.0 1962 4.8 1963 7.9 1964 12.0 1965 14.2 1966 13.6 1967 6.0 1968 3.7 1969 2.9 What is the return period, in years, for a 6.0 cm annual rainfall according to (i) Hazen formula; and (ii) Weibull formula respectively?
uestion No.3 catchment has a net area of 90 ha. After one vear, groundwater table is nonitored, and a sie change is detected. During this year, the average monthly precipitation and evapotranspiration were 20mm and 5mm respectively. In a certain location through the watershed, water dam (Assuming that the lake water depth is 4.0m and evaporation is neglected). Answer Reservoir area
Problem 3. A stream of 175 liters per second was diverted from the river and 105 liters per second was delivered to the field. An area of 2 hectares was irrigated in hours. The root-zone depth was 1.8 m. The runoff averaged 50 liters per second for 3 hours. The depth of water penetration varied linearly from 1.8 m at the head of the field to 1.2 m at the end of the field. Determine the water-conveyance efficiency, the water-application efficiency, * ~ff:
I need solution in half time
Solve for evaporation and precipitation. If u can pls include some explanation, thankyou!