A fitness center is interested in finding a 99% confidence interval for the mean number of daysper week that Americans who are members of a fitness club go to their fitness center. Records of263 members were looked at and their mean number of visits per week was 3.3 and the standarddeviation was 1.9. Round answers to 3 decimal places where possible.a. To compute the confidence interval use a ? v distribution.b. With 99% confidence the population mean number of visits per week is betweenandvisits.c. If many groups of 263 randomly selected members are studied, then a different confidenceinterval would be produced from each group. Aboutpercent of these confidenceintervals will contain the true population mean number of visits per week and aboutpercent will not contain the true population mean number of visits per week.

The random variable number of visits follows normal distribution. We have to construct 99%…

Answered: A fitness center is interested in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The standard deviation, S, for the annual medical cost of 24 households was found to equal $1689 find a 95% confidence interval for the standard deviation of the annual medical cost for all households. Assume medical costs are normally distributed.
A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 268 members were looked at and their mean number of visits per week was 2.1 and the standard deviation was 2.9. a. To compute the confidence interval use a ? distribution. b. With 98% confidence the population mean number of visits per week is between visits. and c. If many groups of 268 randomly selected members are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per week and about percent will not contain the true population mean number of visits per week.
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Suppose the population standard deviation is = 5, an SRS of n = 100 is obtained, and the confidence level is chosen to be 99.5%. The margin of error for estimating a mean is given by: a. 1.576. b. 1.165. c. 1.404. d. 1.223.
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Please help with 6 a-b
A random sample of 64 shoppers showed that they spend an average of $27.31 per visit at the Sunday Mornings Bookstore. The standard deviation of the population is $2.14. Find the 90% confidence interval of the true mean. Please include all work showing how you found your answer.
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is generated in the city. The study included 249 residents whose mean number of pounds of trash generated per person per week was 34.8 pounds and the standard deviation was 7.2 pounds. Round answers to 3 decimal places where possible. b. With 95% confidence the population mean number of pounds per person per week is between ? and ? pounds. c. If many groups of 249 randomly selected members are studied, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population mean number of pounds of trash generated per person per week and about ? percent will not contain the true population mean number of pounds of trash generated per person per week.
A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 271 members were looked at and their mean number of visits per week was 2.3 and the standard deviation was 1.6. a. To compute the confidence interval use a ? distribution. b. With 95% confidence the population mean number of visits per week is between visits. and c. If many groups of 271 randomly selected members are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per week and about percent will not contain the true population mean number of visits per week.
Write up your results as you would see them in a research paper. Be sure that you include the means and standard deviations for each group in your write-up, as well as a sentence or two explaining the results

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