A fishing rod has a mass of O.8 kg. If a fisherman uses 0.8 Nm of torque to give it an angular acceleration of 5 rad/s2, find the length of the fishing rod. Use I = 1/3 m12 for the moment of inertia.

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**Problem: Determining the Length of a Fishing Rod**

A fishing rod has a mass of 0.8 kg. If a fisherman uses 0.8 Nm of torque to give it an angular acceleration of 5 rad/s², find the length of the fishing rod. Use the formula for the moment of inertia: \( I = \frac{1}{3} m l^2 \).

**Solution:**

1. **Identify the given values:**
   - Mass (\( m \)) = 0.8 kg
   - Torque (\( \tau \)) = 0.8 Nm
   - Angular acceleration (\( \alpha \)) = 5 rad/s²

2. **Formula for torque related to angular acceleration:**
   \[
   \tau = I \alpha
   \]
   Where \( I \) is the moment of inertia of the rod.

3. **Substitute the formula for the moment of inertia:**
   \[
   I = \frac{1}{3} m l^2
   \]

4. **Substitute known values into the torque formula:**
   \[
   0.8 = \left(\frac{1}{3} \times 0.8 \times l^2\right) \times 5
   \]

5. **Solve for \( l \):**
   \[
   0.8 = \frac{4}{3} l^2
   \]
   \[
   l^2 = \frac{0.8 \times 3}{4}
   \]
   \[
   l^2 = 0.6
   \]
   \[
   l = \sqrt{0.6}
   \]
   \[
   l \approx 0.775 \, \text{m}
   \]

Therefore, the length of the fishing rod is approximately 0.775 meters.
Transcribed Image Text:**Problem: Determining the Length of a Fishing Rod** A fishing rod has a mass of 0.8 kg. If a fisherman uses 0.8 Nm of torque to give it an angular acceleration of 5 rad/s², find the length of the fishing rod. Use the formula for the moment of inertia: \( I = \frac{1}{3} m l^2 \). **Solution:** 1. **Identify the given values:** - Mass (\( m \)) = 0.8 kg - Torque (\( \tau \)) = 0.8 Nm - Angular acceleration (\( \alpha \)) = 5 rad/s² 2. **Formula for torque related to angular acceleration:** \[ \tau = I \alpha \] Where \( I \) is the moment of inertia of the rod. 3. **Substitute the formula for the moment of inertia:** \[ I = \frac{1}{3} m l^2 \] 4. **Substitute known values into the torque formula:** \[ 0.8 = \left(\frac{1}{3} \times 0.8 \times l^2\right) \times 5 \] 5. **Solve for \( l \):** \[ 0.8 = \frac{4}{3} l^2 \] \[ l^2 = \frac{0.8 \times 3}{4} \] \[ l^2 = 0.6 \] \[ l = \sqrt{0.6} \] \[ l \approx 0.775 \, \text{m} \] Therefore, the length of the fishing rod is approximately 0.775 meters.
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