A fisherman who is fishing 70 ft directly out from a visible tree stump near the shore wants to position his line and bait approximately N32 w of the boat and west of the stump. Using the right triangle shown in the drawing, determine the reef's line counter setting, to the nearest foot, to position the line directiy west of the stump Which of the folowing equations can be used to determine the reefs ine courter setting, d? OA sin 32 70 t Tree Stump Ic. Oc. csc 32- 70t 70 t OD. cos 32 70 t OE tan 32°: 70 m OF. tan 32=O d 32 OG. cos 32" 70 OH. cot 32 70 t OL sec 32°- d 70 O. sin 32 = Soar
A fisherman who is fishing 70 ft directly out from a visible tree stump near the shore wants to position his line and bait approximately N32 w of the boat and west of the stump. Using the right triangle shown in the drawing, determine the reef's line counter setting, to the nearest foot, to position the line directiy west of the stump Which of the folowing equations can be used to determine the reefs ine courter setting, d? OA sin 32 70 t Tree Stump Ic. Oc. csc 32- 70t 70 t OD. cos 32 70 t OE tan 32°: 70 m OF. tan 32=O d 32 OG. cos 32" 70 OH. cot 32 70 t OL sec 32°- d 70 O. sin 32 = Soar
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![A fisherman who is fishing 70 ft directly out from a visible tree stump near the shore wants to position his line and bait approximately N32°W of the boat and west of the stump. Using the right triangle shown in the drawing, determine the reel’s line counter setting, to the nearest foot, to position the line directly west of the stump.
**Diagram Explanation:**
The diagram on the left shows a right triangle labeled with the following:
- Point B represents the tree stump.
- Point A represents the boat.
- Line segment AB is 70 ft, the distance from the boat to the tree stump.
- Angle CAB is 32°.
- Line segment BC is perpendicular to line segment AC.
**Equation Options:**
Which of the following equations can be used to determine the reel’s line counter setting, \( d \)?
A. \(\sin 32^\circ = \frac{d}{70 \text{ ft}}\)
B. \(\csc 32^\circ = \frac{70 \text{ ft}}{d}\)
C. \(\cos 32^\circ = \frac{70 \text{ ft}}{d}\)
D. \(\cos 32^\circ = \frac{d}{70 \text{ ft}}\)
E. \(\tan 32^\circ = \frac{d}{70 \text{ ft}}\)
F. \(\tan 32^\circ = \frac{70 \text{ ft}}{d}\)
G. \(\cos 32^\circ = \frac{d}{70 \text{ ft}}\)
H. \(\cot 32^\circ = \frac{70 \text{ ft}}{d}\)
I. \(\sec 32^\circ = \frac{70 \text{ ft}}{d}\)
J. \(\sin 32^\circ = \frac{70 \text{ ft}}{d}\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd523b0c2-1906-4841-b390-7c0a9a379a7e%2F467e97ba-b3ae-4b38-8b76-f6c4939fec1a%2Fxpgocel_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A fisherman who is fishing 70 ft directly out from a visible tree stump near the shore wants to position his line and bait approximately N32°W of the boat and west of the stump. Using the right triangle shown in the drawing, determine the reel’s line counter setting, to the nearest foot, to position the line directly west of the stump.
**Diagram Explanation:**
The diagram on the left shows a right triangle labeled with the following:
- Point B represents the tree stump.
- Point A represents the boat.
- Line segment AB is 70 ft, the distance from the boat to the tree stump.
- Angle CAB is 32°.
- Line segment BC is perpendicular to line segment AC.
**Equation Options:**
Which of the following equations can be used to determine the reel’s line counter setting, \( d \)?
A. \(\sin 32^\circ = \frac{d}{70 \text{ ft}}\)
B. \(\csc 32^\circ = \frac{70 \text{ ft}}{d}\)
C. \(\cos 32^\circ = \frac{70 \text{ ft}}{d}\)
D. \(\cos 32^\circ = \frac{d}{70 \text{ ft}}\)
E. \(\tan 32^\circ = \frac{d}{70 \text{ ft}}\)
F. \(\tan 32^\circ = \frac{70 \text{ ft}}{d}\)
G. \(\cos 32^\circ = \frac{d}{70 \text{ ft}}\)
H. \(\cot 32^\circ = \frac{70 \text{ ft}}{d}\)
I. \(\sec 32^\circ = \frac{70 \text{ ft}}{d}\)
J. \(\sin 32^\circ = \frac{70 \text{ ft}}{d}\)
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