A fish swimming in a horizontal plane has velocity v = ((4.00)î + (1.00)f)m/s at a point in the ocean where its position relative to a certain rock is r = ((10.0)î – (4.00))m. After the fish swims with constant acceleration for 20.0 s, its velocity becomes v= ((20.0)î - (5.00)f)m/s. What are the horizontal and vertical components of the acceleration (in m/s2)? %3D %3D O a. -1.4, 2.9 Ob.0.8. -0.3 Oc 2.4, -1.5 Od.-0.3, 0.8 Oe 1426

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Chapter1: Units, Trigonometry. And Vectors
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A fish swimming in a horizontal plane has velocity v = ((4.00)î + (1.00)f)m/s at a point in the ocean where its position
relative to a certain rock is r = ((10.0)î – (4.00)))m. After the fish swims with constant acceleration for 20.0 s, its
velocity becomes v ((20.0)î – (5.00)f)m/s. What are the horizontal and vertical components of the acceleration (in
m/s )?
%3D
%3D
O a. -1.4, 2.9
Ob. 0.8, -0.3
Oc 2.4, -1.5
Od.-0.3, 0.8
Oe. 1.4. 2.6
A Moving to the next question prevents changes to this answer.
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Transcribed Image Text:A fish swimming in a horizontal plane has velocity v = ((4.00)î + (1.00)f)m/s at a point in the ocean where its position relative to a certain rock is r = ((10.0)î – (4.00)))m. After the fish swims with constant acceleration for 20.0 s, its velocity becomes v ((20.0)î – (5.00)f)m/s. What are the horizontal and vertical components of the acceleration (in m/s )? %3D %3D O a. -1.4, 2.9 Ob. 0.8, -0.3 Oc 2.4, -1.5 Od.-0.3, 0.8 Oe. 1.4. 2.6 A Moving to the next question prevents changes to this answer. Question 4 of 12 Cose Windo
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