A fish swimming in a horizontal plane has velocity v, = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is i, (14.0 i - 1.60 j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is v = (17.0 i - 6.00 j) m/s. (a) What are the ocomponents of the acceleration of the fish? ay 0.87 m/s? 0.47 m/s? (b) What is the direction of its acceleration with respect to unit vector i? 331.62 counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t= 26.0 s? 412.1 134.46 Remember that you can treat the motions in the x and y directions separately. Each is then treated exactly as you would the one-dimensional case. m In what direction is it moving? 341.54 counterclockwise from the +x-axis Need Help? Master t
A fish swimming in a horizontal plane has velocity v, = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is i, (14.0 i - 1.60 j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is v = (17.0 i - 6.00 j) m/s. (a) What are the ocomponents of the acceleration of the fish? ay 0.87 m/s? 0.47 m/s? (b) What is the direction of its acceleration with respect to unit vector i? 331.62 counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t= 26.0 s? 412.1 134.46 Remember that you can treat the motions in the x and y directions separately. Each is then treated exactly as you would the one-dimensional case. m In what direction is it moving? 341.54 counterclockwise from the +x-axis Need Help? Master t
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![A fish swimming in a horizontal plane has velocity v, = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to
a certain rock is ř, = (14.0 i - 1.60 j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is v = (17.0 i -
6.00 j) m/s.
(a) What are the components of the acceleration of the fish?
V m/s?
v m/s?
ay 0.87
ay =-0.47
(b) What is the direction of its acceleration with respect to unit vector i?
331.62
* counterclockwise from the +x-axis
(c) If the fish maintains constant acceleration, where is it at t= 26.0 s?
X-412.1
134.46
Remember that you can treat the motions in the x and y directions separately. Each is then treated exactly as you
would the one-dimensional case. m
In what direction is it moving?
341.54
* counterclockwise from the +x-axis
Need Help?
Master It](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2b89021-b6f8-44f7-8af4-f3abcd662d19%2F942111b8-21bf-4282-b555-82b93dce62ea%2F86pklur_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A fish swimming in a horizontal plane has velocity v, = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to
a certain rock is ř, = (14.0 i - 1.60 j) m. After the fish swims with constant acceleration for 15.0 s, its velocity is v = (17.0 i -
6.00 j) m/s.
(a) What are the components of the acceleration of the fish?
V m/s?
v m/s?
ay 0.87
ay =-0.47
(b) What is the direction of its acceleration with respect to unit vector i?
331.62
* counterclockwise from the +x-axis
(c) If the fish maintains constant acceleration, where is it at t= 26.0 s?
X-412.1
134.46
Remember that you can treat the motions in the x and y directions separately. Each is then treated exactly as you
would the one-dimensional case. m
In what direction is it moving?
341.54
* counterclockwise from the +x-axis
Need Help?
Master It
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