A fish hatchery manager estimates that on average fisherpersons catch 3.5 fish each fishing trip. A random sample of 50fisherpersons showed they caught 3.9 fish per trip, with a standard deviation of 1.7 fish. a. Solve using a left tailed test of hypothesis and the critical value method. Use a 95% confidence level. b. Solve using a two tailed test of hypothesis and the p-value method. Use a 90% confidence leve

Q: Suppose that textbook weights are normally distributed.  You measure 36 textbooks' weights, and find…

A: Given,   Sample size = 36 Sample mean = 76 Population standard deviation = 6.4   Since the…

Q: In a survey, 31 people were asked how much they spent on their child's last birthday gift. The…

A: Sample size, n = 31Mean = 48Standard deviation = 8

Q: Suppose that your sample size is 3000 and that you wish to construct a 95% confidence interval. Your…

A: From the provided information,n = 3000Confidence level = 95%Sample standard deviation (s) = 42.3

Q: n a survey, 32 people were asked how much they spent on their child's last birthday gift. The…

A: Given that, x¯=$30s=$7n=32 The degree of freedom is, df=n-1    =32-1    =31 Critical value: Using…

Q: In a survey, 29 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=29mean(x¯)=47standard deviation(s)=2α=1-0.95=0.05α2=0.025Degrees of…

Q: A student group claims that first-year students at a university study 2.5 hours per night during the…

A: Given thatA student group claims that first-year students at a university study 2.5 hours per night…

Q: Homes in a nearby college town have a mean value of $88,950. It's assumed that homes in the vicinity…

A:

Q: In a survey, 11 people were asked how much they spent on their child's last birthday gift. The…

A: We have to find margin of error

Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: The operations manager of a large production plant would like to estimate the average amount of time…

A: Given:Confidence level = 91.28%

Q: You measure 35 watermelons' weights, and find they have a mean weight of 34 ounces. Assume the…

A: According to the given information in this question We need to find the margin of error

Q: maximal margin of error associated with a 90% confidence interval for the true population mean…

A: You measure 45 watermelon's weights, and find they have mean weight of 68 ounces.  population…

Q: An admission officer of Gabaldon Vocational Agriculture High School wants to know the mean age of…

A: Note, Since you have posted a question with multiple sub-parts, we will solve first three sub-parts…

Q: Give the best point estimate for the population and construct a 99% confidence interval for the true…

A: Let μ be the population mean score for students. Given that, x¯= 3.4Sample size (n) = 26Sample…

Q: The operations manager of a large production plant would like to estimate the average amount of time…

A: The standard deviation is 7 minutes; σ=7minutes Margin of error=22 seconds Confidence level is…

Q: In a survey, 27 people were asked how much they spent on their child's last birthday gift. The…

A: Since the population standard deviation is unknown, t distribution can be used for the computation…

Q: A fundraiser for a political party believes that for every letter mailed, the average contribution…

A: The one-sample z-test is used to test whether the mean of a population is greater than, less than,…

Q: sample of 40 observations is selected from a normal population where the population variance is 625.…

A: According to the given information in this questionThere are more than three subparts according to…

Q: na survey, 29 people were asked how much they spent on th vere roughly bell-shaped with a mean of…

A:

Q: at the university spend on groceries each month. From a sample of 29 random students, you find that…

A: Given that  Sample size n =29 Sample mean =871.35 Standard deviation =235.06 NOTE:- According to…

Q: A 2016 study reported in Science magazine stated that college math teachers scored a mean of 3.4…

A:

Q: In a survey, 13 people were asked how much they spent on their child's last birthday gift. The…

A: Given, Sample size, n = 13 Sample mean = 44 Sample standard deviation, s = 10 Confidence level = 80%…

Q: In a survey, 30 people were asked how much they spent on their child's last birthday gift. The…

A: We have given that,  Sample mean (x̄) = $ 44, standard deviation (s) = $ 10, sample size (n) = 30…

Q: A researcher records the repair cost for 13 randomly selected stereos. A sample mean of $85.52 and…

A: Given n =13 Sample mean, x = $85.52 Sample standard deviation, s = $10.81

Q: Assume that you want to construct a​ 95% confidence interval estimate of a population mean. Find an…

A:

Q: Suppose that textbook weights are normally distributed. You measure 26 textbooks' weights, and find…

A:

Q: Based on this, construct a 99% confidence interval for the true population mean textbook weight

A: Sample size n = 42 Sample mean = 80 Population SD = 10.3 And the critical value of Z at 99%…

Q: You measure 42 watermelons' weights, and find they have a mean weight of 70 ounces. Assume the…

A: Critical value: The value of α is 0.05 for 95% confidence level. Using excel formula…

Q: A survey of 50 young professionals found that they spent an average of $20 confidence interval. The…

A: Sample mean = x̅ = 20.09 Sample size = n = 50 Sample S.D = s = 11.12 Standard Error = s/√n  =…

Q: You measure 44 textbooks' weights, and find they have a mean weight of 66 ounces. Assume the…

A: From the given information, sample mean, x̅=66 ounces Population standard deviation, σ=9 ounces…

Q: A survey of 25 randomly selected iPhone owners showed that the purchase price has a mean of $397…

A:

Q: How much does a sleeping bag cost? Backpacker Magazine took a random sample of the cost of 31…

A: Given: n = 31 X = 119.75 s = 17.20 Formula Used: Confidence Interval = X ± tsn

Q: A librarian estimates that patrons check out, on the average, 4.2 books per visit. A random sample…

A: The following information is provided: patrons check out, on the average, 4.2 books per visit…

Q: Suppose that textbook weights are normally distributed.  You measure 26 textbooks' weights, and find…

A: Given: Since we know population standard deviation, use z-distribution. Find z-critical value:…

Q: Suppose that textbook weights are normally distributed.  You measure 23 textbooks' weights, and find…

A: Given that  Sample size n =23 Sample mean=74 Population standard deviation =15

Q: You measure 28 turtles' weights, and find they have a mean weight of 75 ounces. Assume the…

A: sample size(n)=28Mean()=75standard deviation()=14.2confidence level=99%

Q: You measure 31 textbooks' weights, and find they have a mean weight of 33 ounces. Assume the…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Q: In a survey, 11 people were asked how much they spent on their child's last birthday gift. The…

A: Since population standard deviation is unknown, use t-distribution to find t-critical value. Find…

Q: You measure 42 randomly selected textbooks' weights, and find they have a mean weight of 41 ounces.…

A: Given problem Given that   x̄ = 41 σ = 4.4 N = 42 As we know, P( -1.96 < z < 1.96 ) = 0.95…

Q: The students in Juan's math class have the exact same mean height as the students in Juan's English…

A:

Q: The Pew Research Center conducts an annual Internet Project, which includes research related to…

A: The table shows the percentage of adults surveyed who use at least one social media site, broken…

Q: You measure 47 watermelons' weights, and find they have a mean weight of 35 ounces. Assume the…

A:

Q: Many medical professionals believe that smoking increases the risk of heart disease and cancer. A…

A: From the given information, it is obtained that: σ (population standard deviation)=12Confidence…

Q: Suppose that textbook weights are normally distributed.  You measure 20 textbooks' weights, and find…

A: According to the provided information, Mean (x̅) = 53 Standard deviation (σ) = 10.2 Sample size (n)…

Q: A sociologist develops a test to measure attitudes towards public transportation, and 37 randomly…

A: given that,sample mean, x =58.5standard deviation, s =19.7sample size, n =37standard error = sd/…