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A fireworks show is choreographed to have two shells cross paths at a height of 176 feet and explode at an apex of 219 feet under normal weather conditions. If the shells have a launch angle = 55° above the horizontal, determine the common launch speed vo fo the shells, the separation distance d between the launch points A and B, and the time t from launch at which the shells explode. 43' 176' Vo 0 d B

A fireworks show is choreographed to have two shells cross paths at a height of 176 feet and explode at an apex of 219 feet under normal weather conditions. If the shells have a launch angle = 55° above the horizontal, determine the common launch speed vo fo the shells, the separation distance d between the launch points A and B, and the time t from launch at which the shells explode. 43' 176' Vo 0 d B

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A fireworks show is choreographed to have two shells cross paths at a height of 176 feet and explode at an apex of 219 feet under normal weather conditions. If the shells have a launch angle = 55° above the horizontal, determine the common launch speed vo f the shells, the separation distance d between the launch points A and B, and the time t from launch at which the shells explode. 7 43' 176' d B
Transcribed Image Text:A fireworks show is choreographed to have two shells cross paths at a height of 176 feet and explode at an apex of 219 feet under normal weather conditions. If the shells have a launch angle = 55° above the horizontal, determine the common launch speed vo f the shells, the separation distance d between the launch points A and B, and the time t from launch at which the shells explode. 7 43' 176' d B
Determine the common launch speed vo for the shells. ↑ 43' 176' Answer: Vo = VO A/0 Mi 1 A I -d C ft/sec I A VO 0 B
Transcribed Image Text:Determine the common launch speed vo for the shells. ↑ 43' 176' Answer: Vo = VO A/0 Mi 1 A I -d C ft/sec I A VO 0 B
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