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a) Finish the following truth table of a 2-to-4 binary decoder with active-high output, whose logic symbol is shown below. Assume that 'x1' is the most significant bit in the input and 'x0' is the least significant bit in the input. x1 z0 2-to-4 z1 x0 decoder z2 z3 x1 x0 zo zl z2 z3 b) Use the 2-to-4 decoder above to implement the logic function F(x1,x0) = (x1+ x0)(x1+x0). You may use an additional logic gate.

a) Finish the following truth table of a 2-to-4 binary decoder with active-high output, whose logic symbol is shown below. Assume that 'x1' is the most significant bit in the input and 'x0' is the least significant bit in the input. x1 z0 2-to-4 z1 x0 decoder z2 z3 x1 x0 zo zl z2 z3 b) Use the 2-to-4 decoder above to implement the logic function F(x1,x0) = (x1+ x0)(x1+x0). You may use an additional logic gate.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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a) Finish the following truth table of a 2-to-4 binary decoder with active-high output, whose logic symbol is shown below. Assume that 'x1' is the most significant bit in the input and 'x0' is the least significant bit in the input. x1 zo 2-to-4 z1 x0 decoder z2 z3 x1 x0 z0 zl z2 z3 b) Use the 2-to-4 decoder above to implement the logic function F(x1,x0) = (x1+ x0)(x1+x0). You may use an additional logic gate.
Transcribed Image Text:a) Finish the following truth table of a 2-to-4 binary decoder with active-high output, whose logic symbol is shown below. Assume that 'x1' is the most significant bit in the input and 'x0' is the least significant bit in the input. x1 zo 2-to-4 z1 x0 decoder z2 z3 x1 x0 z0 zl z2 z3 b) Use the 2-to-4 decoder above to implement the logic function F(x1,x0) = (x1+ x0)(x1+x0). You may use an additional logic gate.
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