a) Find the value of p such that the series -1 E(-1)2n+1 is a 9-series nºp n=4 Answer: p = b) Find the value of r such that the serie E(-1)"- is equal to - n=0 Answer: r = c) For which value of k the series 3 (-1)2n+221-"2k-1 is equal to 1
a) Find the value of p such that the series -1 E(-1)2n+1 is a 9-series nºp n=4 Answer: p = b) Find the value of r such that the serie E(-1)"- is equal to - n=0 Answer: r = c) For which value of k the series 3 (-1)2n+221-"2k-1 is equal to 1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![a) Find the value of p such that the series
E(-1)2n+1
is a 9-series
nºp
n=4
Answer:
p =
b) Find the value of r such that the serie
1
is equal to -
1
E(-1y".
n=0
Answer:
r =
c) For which value of k the series
00
3 (-1)2n+2 21-n2k-1 is equal to 1
n=0
Answer:
k =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda700188-ae26-439e-99a6-c1f445823b3f%2F390cf4b0-a5ca-404b-8c18-d20c5b9080c1%2Fd4vr34j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:a) Find the value of p such that the series
E(-1)2n+1
is a 9-series
nºp
n=4
Answer:
p =
b) Find the value of r such that the serie
1
is equal to -
1
E(-1y".
n=0
Answer:
r =
c) For which value of k the series
00
3 (-1)2n+2 21-n2k-1 is equal to 1
n=0
Answer:
k =
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