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a) Find the value of p such that the series 00 E(-12n+1 n10p -1 is a 10-series n=4 Answer: p = 1 b) Find the value of r such that the serie 00 E(-1)"- is equal to . If it is not possible write n=0 NP in the box. Answer: r = NP c) For which value of k the series 00 3 (-1)2"2-"2k-l is equal to 1. If it is not n=0 possible write NP in the box. Answer:

a) Find the value of p such that the series 00 E(-12n+1 n10p -1 is a 10-series n=4 Answer: p = 1 b) Find the value of r such that the serie 00 E(-1)"- is equal to . If it is not possible write n=0 NP in the box. Answer: r = NP c) For which value of k the series 00 3 (-1)2"2-"2k-l is equal to 1. If it is not n=0 possible write NP in the box. Answer:

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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a) Find the value of p such that the series 00 2(-1)2n+1_-1 n10p is a 10-series n=4 Answer: p 3D 1 b) Find the value of r such that the serie 00 E(-1)"- is equal to . If it is not possible write n=0 NP in the box. Answer: r = NP c) For which value of k the series 00 E(-1)2"2-"2k-1 is equal to 1. If it is not 2 n=0 possible write NP in the box. Answer: k -0.58496
Transcribed Image Text:a) Find the value of p such that the series 00 2(-1)2n+1_-1 n10p is a 10-series n=4 Answer: p 3D 1 b) Find the value of r such that the serie 00 E(-1)"- is equal to . If it is not possible write n=0 NP in the box. Answer: r = NP c) For which value of k the series 00 E(-1)2"2-"2k-1 is equal to 1. If it is not 2 n=0 possible write NP in the box. Answer: k -0.58496
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