(a) Find the slope of the curve y=x³-7x at the given point P(1,-6) by finding the limiting value of the slope of the secants through P. (b) Find an equation of the tangent line to the curve at P(1,-6). (a) The slope of the curve at P(1,-6) is (b) The equation of the tangent line to the curve at P(1, - 6) is y= ...
(a) Find the slope of the curve y=x³-7x at the given point P(1,-6) by finding the limiting value of the slope of the secants through P. (b) Find an equation of the tangent line to the curve at P(1,-6). (a) The slope of the curve at P(1,-6) is (b) The equation of the tangent line to the curve at P(1, - 6) is y= ...
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter7: Integration
Section7.1: Antiderivatives
Problem 45E
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![(a) Find the slope of the curve y=x³-7x at the given point P(1, -6) by finding the limiting value of the slope of the secants through P.
(b) Find an equation of the tangent line to the curve at P(1,-6).
(a) The slope of the curve at P(1, -6) is
(b) The equation of the tangent line to the curve at P(1, - 6) is y=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff573b781-3d73-4ea1-a5e1-29d89752d87e%2F5cb33465-2271-4bcc-b3b8-d6151c1e8059%2F2xl7w5a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(a) Find the slope of the curve y=x³-7x at the given point P(1, -6) by finding the limiting value of the slope of the secants through P.
(b) Find an equation of the tangent line to the curve at P(1,-6).
(a) The slope of the curve at P(1, -6) is
(b) The equation of the tangent line to the curve at P(1, - 6) is y=
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