a) Find the no-load value of v, in the circuit shown. 3.2 3. b) Find v, when Rµ is 150 kN. c) How much power is dissipated in the 25 kN resistor if the load terminals are accidentally short-circuited?

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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ASSESSMENT PROBLEMS
Objective 2–Know how to design simple voltage-divider and current-divider circuits
a) Find the no-load value of v, in the
circuit shown.
a) Find the value of R that will cause 4 A of
current to flow through the 80N resistor in
the circuit shown.
3.2
3.3
b) Find v, when R, is 150 kN.
b) How much power will the resistor R from
part (a) need to dissipate?
c) How much power will the current source
generate for the value of R from part (a)?
c) How much power is dissipated in the 25 kN
resistor if the load terminals are accidentally
short-circuited?
d) What is the maximum power dissipated in
the 75 kN resistor?
60 Ω
325 kN
40 Ωξ
200 V
20 A
80 Ωξ
375 kN
RL
Answer: (a) 150 V;
Answer: (a) 30 N;
(b) 133.33 V;
(b) 7680 W;
(c) 1.6 W;
(c) 33,600 W.
(d) 0.3 W.
NOTE: Also try Chapter Problems 3.12, 3.14, and 3.16.
Transcribed Image Text:ASSESSMENT PROBLEMS Objective 2–Know how to design simple voltage-divider and current-divider circuits a) Find the no-load value of v, in the circuit shown. a) Find the value of R that will cause 4 A of current to flow through the 80N resistor in the circuit shown. 3.2 3.3 b) Find v, when R, is 150 kN. b) How much power will the resistor R from part (a) need to dissipate? c) How much power will the current source generate for the value of R from part (a)? c) How much power is dissipated in the 25 kN resistor if the load terminals are accidentally short-circuited? d) What is the maximum power dissipated in the 75 kN resistor? 60 Ω 325 kN 40 Ωξ 200 V 20 A 80 Ωξ 375 kN RL Answer: (a) 150 V; Answer: (a) 30 N; (b) 133.33 V; (b) 7680 W; (c) 1.6 W; (c) 33,600 W. (d) 0.3 W. NOTE: Also try Chapter Problems 3.12, 3.14, and 3.16.
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