(a) Find the far point of an eye for which a prescribed lens has an optical power of -0.48 d. (b) Find the far point of an eye for which a prescribed lens has an optical power of -4.4 d.

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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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### Far Point Calculation for Prescribed Lenses

In this section, we will learn how to calculate the far point of the eye based on the optical power of prescribed lenses. 

#### Example Problems:

(a) **Problem:**
   Find the far point of an eye for which a prescribed lens has an optical power of -0.48 diopters (d).

   **Solution Box:**
   [___________]

(b) **Problem:**
   Find the far point of an eye for which a prescribed lens has an optical power of -4.4 diopters (d).

   **Solution Box:**
   [___________]

### Explanation:
The far point is the maximum distance at which the eye can see objects clearly. For someone who is nearsighted (myopic), the far point is closer than infinity. The optical power (D) of the lens needed to correct vision is related to the far point (f) in meters by the formula:

\[ D = \frac{1}{f} \]

Here, D is given in diopters (d), and f is the far point in meters.

### To Solve:
1. To find the far point \( f \), rearrange the formula: 

\[ f = \frac{1}{D} \]

2. Substitute the given values of optical power (D) into the formula to find the far point for each problem.

3. Ensure to convert the final answer into appropriate units (meters).

By solving these examples, you will better understand how to assess and calculate the visual needs for corrective lenses.
Transcribed Image Text:### Far Point Calculation for Prescribed Lenses In this section, we will learn how to calculate the far point of the eye based on the optical power of prescribed lenses. #### Example Problems: (a) **Problem:** Find the far point of an eye for which a prescribed lens has an optical power of -0.48 diopters (d). **Solution Box:** [___________] (b) **Problem:** Find the far point of an eye for which a prescribed lens has an optical power of -4.4 diopters (d). **Solution Box:** [___________] ### Explanation: The far point is the maximum distance at which the eye can see objects clearly. For someone who is nearsighted (myopic), the far point is closer than infinity. The optical power (D) of the lens needed to correct vision is related to the far point (f) in meters by the formula: \[ D = \frac{1}{f} \] Here, D is given in diopters (d), and f is the far point in meters. ### To Solve: 1. To find the far point \( f \), rearrange the formula: \[ f = \frac{1}{D} \] 2. Substitute the given values of optical power (D) into the formula to find the far point for each problem. 3. Ensure to convert the final answer into appropriate units (meters). By solving these examples, you will better understand how to assess and calculate the visual needs for corrective lenses.
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