A) Find the equivalent resistance of the arrangement. B) Find the voltage across the 8 Ohm resistor. C) Find the current through the 8 Ohm resistor. D) Find the power of the 8 Ohm resistor. each of these 3 A are 362 LMW www 82 B AVAB 3222 www. = 20 volts 32r each of these 4 are 162
A) Find the equivalent resistance of the arrangement. B) Find the voltage across the 8 Ohm resistor. C) Find the current through the 8 Ohm resistor. D) Find the power of the 8 Ohm resistor. each of these 3 A are 362 LMW www 82 B AVAB 3222 www. = 20 volts 32r each of these 4 are 162
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Question
![**Question 4**
A) Find the equivalent resistance of the arrangement.
B) Find the voltage across the 8 Ohm resistor.
C) Find the current through the 8 Ohm resistor.
D) Find the power of the 8 Ohm resistor.
**Circuit Description:**
The circuit diagram illustrated consists of several resistors arranged in a mixed combination of series and parallel. It is structured as follows:
1. There are three resistors, each of 36 Ω, connected in parallel.
2. One 8 Ω resistor is connected in series with the group of three parallel 36 Ω resistors.
3. After the 8 Ω resistor, two 32 Ω resistors are arranged in parallel.
4. Finally, four 16 Ω resistors are arranged in parallel, tied into the network after the parallel 32 Ω resistors.
5. Points A and B indicate the terminals across which the voltage (ΔV_AB = 20 volts) is measured.
**Diagrams:**
1. **Parallel Combination of 36 Ω Resistors:**
```
[36 Ω]
|
[36 Ω]
|
[36 Ω]
- These resistors are connected in parallel.
```
2. **Series Composition:**
```
8 Ω (series)
```
3. **Parallel Connection of 32 Ω Resistors:**
```
[32 Ω]
|
[32 Ω]
- Two 32 Ω resistors connected in parallel.
```
4. **Parallel Connection of 16 Ω Resistors:**
```
[16 Ω]
|
[16 Ω]
|
[16 Ω]
|
[16 Ω]
- Four 16 Ω resistors connected in parallel.
```
**Calculations:**
- **Total Resistance for 36 Ω Resistors in Parallel:**
- \( \frac{1}{R_{parallel}} = \frac{1}{36} + \frac{1}{36} + \frac{1}{36} \)
- \( R_{parallel} = 12 \) Ω
- **Combined Resistance with 8 Ω Resistor in Series:**
- \( R = 12 Ω + 8 Ω = 20 Ω \)
- **Total Resistance for 32 Ω Resistors in Parallel:**
- \( \frac{1}{R_{parallel}} = \frac{1}{32} + \frac{1}{32} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F290bf5a5-1401-4039-a263-550aca887643%2F9e138417-0847-4331-a3f7-64a1f438b874%2Fdnzdqw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 4**
A) Find the equivalent resistance of the arrangement.
B) Find the voltage across the 8 Ohm resistor.
C) Find the current through the 8 Ohm resistor.
D) Find the power of the 8 Ohm resistor.
**Circuit Description:**
The circuit diagram illustrated consists of several resistors arranged in a mixed combination of series and parallel. It is structured as follows:
1. There are three resistors, each of 36 Ω, connected in parallel.
2. One 8 Ω resistor is connected in series with the group of three parallel 36 Ω resistors.
3. After the 8 Ω resistor, two 32 Ω resistors are arranged in parallel.
4. Finally, four 16 Ω resistors are arranged in parallel, tied into the network after the parallel 32 Ω resistors.
5. Points A and B indicate the terminals across which the voltage (ΔV_AB = 20 volts) is measured.
**Diagrams:**
1. **Parallel Combination of 36 Ω Resistors:**
```
[36 Ω]
|
[36 Ω]
|
[36 Ω]
- These resistors are connected in parallel.
```
2. **Series Composition:**
```
8 Ω (series)
```
3. **Parallel Connection of 32 Ω Resistors:**
```
[32 Ω]
|
[32 Ω]
- Two 32 Ω resistors connected in parallel.
```
4. **Parallel Connection of 16 Ω Resistors:**
```
[16 Ω]
|
[16 Ω]
|
[16 Ω]
|
[16 Ω]
- Four 16 Ω resistors connected in parallel.
```
**Calculations:**
- **Total Resistance for 36 Ω Resistors in Parallel:**
- \( \frac{1}{R_{parallel}} = \frac{1}{36} + \frac{1}{36} + \frac{1}{36} \)
- \( R_{parallel} = 12 \) Ω
- **Combined Resistance with 8 Ω Resistor in Series:**
- \( R = 12 Ω + 8 Ω = 20 Ω \)
- **Total Resistance for 32 Ω Resistors in Parallel:**
- \( \frac{1}{R_{parallel}} = \frac{1}{32} + \frac{1}{32} \)
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