(a) Find the charge on a baseball, thrown at 35.0 m/s perpendicular to the Earth’s 5.00×10-5 T field, that experiences a 1.00-N magnetic force. (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?

Q: An oxygen-16 ion with a mass of 2.66·10−26 kg travels at 5·106 m/s perpendicular to a 1.20 T…

A:

Q: A proton is moving at 2000 m/s through an electric field with E = 15,000 N/C as shown below. What…

A: The velocity of the particle, electric field and magnetic field all are perpendicular to each other.…

Q: An electron accelerated through a potential di 2.5 kV, moves horizontally into a region of space in…

A:

Q: A  copper wire hangs vertically from a tree limb down to the ground, 3.0 meters below. A child…

A: Given, Magnetic field, B=1.5×10-4 T Angle with horizontal,θ=22° Force, F=0.05 N Length of wire, L=3…

Q: An electron in a TV CRT moves with a speed of 6.00 X 107 m/s,in a direction perpendicular to the…

A: velocity, v = 6 X 107 m/s magnetic field, B  = 5 X 10-5 T

Q: A physicist performing a sensitive measurement wants to limit the magnetic force on a moving point…

A: solution is given as

Q: Suppose a 3mC charge moves with velocity 817.82 m/s at an angle of 36.43° relative to the direction…

A: Given:-              charge  q=3mC=3×10-3Cvelocity   v=817.82 m/s               θ=36.43°magnetic…

Q: An electron (m=9.1 x 10-31 kg, q=-1.6x10-19 C) traveling at a speed of 2.1 x 108 m/s in the +…

A: Given Mass of electron = m = 9.1 x 10-31 kg charge on electron = q = -1.6x10-19 C speed of electron…

Q: An electron travels at a speed of 9.5 x 106 m/s in a magnetic field of 1.16 x 10-3 T. As result of…

A:

Q: As shown in the figure below, when a charged particle enters a region of magnetic field traveling in…

A: (a)   Write the expression for the magnetic force. F=qv×B From the right-hand rule, the velocity and…

Q: A particle of charge -6.25 nC experiences a force of 1.25 N when it is moving at 3.75 x 10^4 m/s.…

A: Write the given values with the suitable variables. q=-6.25 nC=-6.25×10-9 CF=1.25 Nv=3.75×104 m/sr=3…

Q: Consider a lightning bolt at the equator that carries 22000 A. What is the magnitude of the…

A:

Q: A particle with a charge of -3.5×10−8 C  is moving with an instantaneous velocity of magnitude 50.0…

A: The velocity in the x-direction is calculated as, The magnetic field in -x direction is, The…

Q: when a charged particle enters a region of magnetic field traveling in a direction perpendicular to…

A: Magnetic field strength (B) = 0.18 T speed of particle (v) = 12×106 msRadius of trajectory (R) = 106…

Q: A magnet produces a 0.50-T uniform field between its poles, directed to the east. A dust particle…

A: Magnetic field (B→) = 0.5 T i^Charge on dust particle (q) = -4×10-18 C Velocity of dust particle…

Q: Calculate the magnitude and direction of the magnetic force on an electron moving with a velocity of…

A: Given Velocity (v)            = 7.0×104 j m/s Magnetic field (B) = 0.57 (k) T

Q: A particle with positive charge a- 4.19x 10 1 C moves with a velocity v- (4i + 4j - k) m/s through a…

A:

Q: What force is felt by a 9.0 nC charge moving at a velocity of 3.0 × 10^4 m/s at an angle of 10° to a…

A: Given,  charge , q = 9.0 nC = 9.0×10-9 C velocity ,v = 3.0 ×104 m/s Magnetic field , B = 8.0×10-4 T…

Q: An alpha particle (the nucleus of a helium atom), carrying a charge of 3.2 × 10^−19 C moves at 4.4 ×…

A: Charge on the particle, q=3.2×10-19 C Velocity of the particle, v=4.4×107 m/s Force on the particle,…

Q: A 0.140-kg baseball, pitched at 37.5 m/s horizontally and perpendicular to the Earth’s horizontal…

A: Given: Mass,m=0.140kgFinal Vecloity,v=37.5m/sInitial Vecloity,u=0m/sMagnetic…

Q: a region where there is both an electric field E~ pointing upward (shown in the figure below), and…

A:

Q: The earth's magnetic field can affect the electron beam in an oscilloscope or a television tube. An…

A: Potential difference =  3.96×104 V B of earth =  0.25×10-4 T

Q: A particle with a charge of -3.5×10−8 C  is moving with velocity of magnitude 50.0 km/s in the x-y…

A: GivenCharge on particle magnitude of velocity angle

Q: An ion with charge 4.8x10-19 C and a mass of 7.95 x 10−26 kg10−26 kg travels perpendicular to a 1.15…

A: Given data is, q=4.8×10-19 Cm=7.95×10-26 Kgθ=900B=1.15 TR=33.5 cm=0.335 mV=Velocity=?

Q: Find the force the magnetic field exerts on the particle

A:

Q: Find the magnitude and direction.

A:

Q: Calculate the magnitude and direction of the magnetic force on an electron moving with a velocity of…

A: Given, velocity of electron , v =  5.0 × 104 (i) m/s Magnetic field, B = 0.67 (j) T We know that…

Q: (a) An electron moves through a uniform electric field E = (2.801 + 5.80J) V/m and a uniform…

A:

Q: What is the force on an electron moving in the negative-z direction with a speed of 2.5 x 106 m/s in…

A: Given: The speed of the electron in the negative z-direction is v=2.5×106 m/s The magnetic field in…

Q: 14. A particle with a charge of 7.7 uC and a speed of 435 m/s is acted on by both and electric and a…

A: See below

Q: (a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron…

A:

Q: An electron is accelerated through 2.55 x 10³ V from rest and then enters a uniform 1.30-T magnetic…

A:

Q: A cosmic ray proton moving toward the Earth at 14.00×10^7m/s experiences a magnetic force of…

A: Given:- Velocity of the proton is vp=14.00×107 m/s Magnetic force on the comic ray proton is…

Q: Consider a lightning bolt where 15C of charge flows for 1.5x10^3 s. Assume that the magnitude of the…

A:

Q: A charge moves in a circle in a magnetic field at 12 m/s. If the 2 x10−5 T field points out of the…

A: Velocity of charge, v=12 m/sMagnetic field, B=2×10-5 TRadius of circle, r=5 cm=0.05 mCharge, q=3…

Q: As shown in the figure below, when a charged particle enters a region of magnetic field traveling in…

A: Given, Magnetic field B=0.18T Speed of the particle v=12×106 m/s Radius of trajectory r=105 cm=1.05…

Q: A 25 m wire stretched horizontally between two vertical posts, carries a current of 60 A. The wire…

A: