a) Find P(at least 7)= b)Find P(at most 5)= ENTER YOUR ANSWER TO 2 DECIMAL PLACES
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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a) Find P(at least 7)=
b)Find P(at most 5)=
ENTER YOUR ANSWER TO 2 DECIMAL PLACES
![The table shown represents a probability distribution with calculations of expected values. It includes the following columns:
1. **X**: A random variable taking values 3, 4, 5, 6, 7, and 8.
2. **P(X)**: The probability associated with each value of X.
- P(3) = 0.18
- P(4) = 0.2
- P(5) = 0.17
- P(6) = 0.42
- P(7) = 0.02
- P(8) = 0.01
3. **X P(X)**: The product of the random variable X and its probability P(X), which represents the contribution of each value to the expected value of X.
- 3 * 0.18 = 0.54
- 4 * 0.2 = 0.80
- 5 * 0.17 = 0.85
- 6 * 0.42 = 2.52
- 7 * 0.02 = 0.14
- 8 * 0.01 = 0.08
The sum of these values, Σ X P(X), is 4.93.
4. **X² P(X)**: The product of the square of the random variable X and its probability P(X), which is used in variance calculations.
- 3² * 0.18 = 1.62
- 4² * 0.2 = 3.20
- 5² * 0.17 = 4.25
- 6² * 0.42 = 15.12
- 7² * 0.02 = 0.98
- 8² * 0.01 = 0.64
The sum of these values, Σ X² P(X), is 25.81.
The table includes totals at the bottom:
- The total probability Σ P(X) is 1, confirming the probabilities are correctly normalized.
- Σ X P(X) = 4.93, the expected value of X.
- Σ X² P(X) = 25.81, useful for calculating variance and standard deviation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa29210f1-c509-4cc5-a424-b61c622bd259%2Fa92d3fd2-a255-4fe8-98e8-4af510609042%2Fph3tmmo_processed.png&w=3840&q=75)
Transcribed Image Text:The table shown represents a probability distribution with calculations of expected values. It includes the following columns:
1. **X**: A random variable taking values 3, 4, 5, 6, 7, and 8.
2. **P(X)**: The probability associated with each value of X.
- P(3) = 0.18
- P(4) = 0.2
- P(5) = 0.17
- P(6) = 0.42
- P(7) = 0.02
- P(8) = 0.01
3. **X P(X)**: The product of the random variable X and its probability P(X), which represents the contribution of each value to the expected value of X.
- 3 * 0.18 = 0.54
- 4 * 0.2 = 0.80
- 5 * 0.17 = 0.85
- 6 * 0.42 = 2.52
- 7 * 0.02 = 0.14
- 8 * 0.01 = 0.08
The sum of these values, Σ X P(X), is 4.93.
4. **X² P(X)**: The product of the square of the random variable X and its probability P(X), which is used in variance calculations.
- 3² * 0.18 = 1.62
- 4² * 0.2 = 3.20
- 5² * 0.17 = 4.25
- 6² * 0.42 = 15.12
- 7² * 0.02 = 0.98
- 8² * 0.01 = 0.64
The sum of these values, Σ X² P(X), is 25.81.
The table includes totals at the bottom:
- The total probability Σ P(X) is 1, confirming the probabilities are correctly normalized.
- Σ X P(X) = 4.93, the expected value of X.
- Σ X² P(X) = 25.81, useful for calculating variance and standard deviation.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given probability distribution table:
X | P(X) |
3 | 0.18 |
4 | 0.2 |
5 | 0.17 |
6 | 0.42 |
7 | 0.02 |
8 | 0.01 |
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