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(a) Find an equation of the tangent plane to the surface at the given point. xyz = 12, (1, 4, 3) (b) Find a set of symmetric equations for the normal line to the surface at the given point. O x + 1 _ y + 4 z + 3 12 3 4 OX + 1 12 y + 4 z + 3 4 OX-1 12 Ox - 1 = y - 4 = z - 3 y - 4 3. Z - 3 4 II N

(a) Find an equation of the tangent plane to the surface at the given point. xyz = 12, (1, 4, 3) (b) Find a set of symmetric equations for the normal line to the surface at the given point. O x + 1 _ y + 4 z + 3 12 3 4 OX + 1 12 y + 4 z + 3 4 OX-1 12 Ox - 1 = y - 4 = z - 3 y - 4 3. Z - 3 4 II N

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(a) Find an equation of the tangent plane to the surface at the given point. xyz = 12, (1, 4, 3) (b) Find a set of symmetric equations for the normal line to the surface at the given point. O x + 1_ y + 4 z + 3 12 3 4 O x + 1 y + 4 z + 3 12 4 3 Ox - 1 = y – 4 = z 3 OX- 1 12 y 4 Z - 3 3 4 y 12 4 3
Transcribed Image Text:(a) Find an equation of the tangent plane to the surface at the given point. xyz = 12, (1, 4, 3) (b) Find a set of symmetric equations for the normal line to the surface at the given point. O x + 1_ y + 4 z + 3 12 3 4 O x + 1 y + 4 z + 3 12 4 3 Ox - 1 = y – 4 = z 3 OX- 1 12 y 4 Z - 3 3 4 y 12 4 3
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(a) Find an equation of the tangent plane to the surface at the given point. xyz = 12, (1, 4, 3) 12x + 3y + 4: = 36 (b) Find a set of symmetric equations for the normal line to the surface at the given point. x + 1 _ y + 4 z + 3 12 3 4 x + 1 y + 4 z + 3 12 4 3 Ox - 1 = y - 4 = z - 3 %3D OX-1 12 y - 4 z - 3 3 y %3D 12 4 3 4.
Transcribed Image Text:(a) Find an equation of the tangent plane to the surface at the given point. xyz = 12, (1, 4, 3) 12x + 3y + 4: = 36 (b) Find a set of symmetric equations for the normal line to the surface at the given point. x + 1 _ y + 4 z + 3 12 3 4 x + 1 y + 4 z + 3 12 4 3 Ox - 1 = y - 4 = z - 3 %3D OX-1 12 y - 4 z - 3 3 y %3D 12 4 3 4.
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