n AssighimentDURCESectionsion 1-CI,Eion 1-CI,(c) If we want a margin of error of only ±0.5 with 90% confidence, what sample size is needed?tion 1-CI,Round your answer up to the nearest integer.tion 1-CI,sample size =ction 1-CI,the absolute tolerance is +/-3ection 1-CI,Click if you would like to Show Work for this question: Open Show Workection 1-CI.ection 1-D,Section 1-D,By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instruciSection 1-D,QueSection 1-e 046Section 1-Le 047Section 1-se 048Section 1-se 050- Section 1-ise 0565. Section 1-%powered byManleNeteement | Privacy Policy I Q 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc.MacBook ProTheI'm#2$4.%378.RDH6.CD AssignmentGradebookORIONDownloadable eTextbookentFULL SCREENPRINTER VERSION1 BACKNEXTChapter 6, Section 2-CI, Exercise 108Plastic Microfiber Pollution on ShorelinesIn a study, we see that plastic microparticles are contaminating the world's shorelines and that much of the pollution appears to come from fibers from washing polyester clothes. The same study alsotook samples from ocean beaches. Five samples were taken from each of 18 different shorelines worldwide, for a total of 90 samples of size 250 mL. The mean number of plastic microparticles foundper 250 mL of sediment was 18.3 with a standard deviation of 8.2.(a) Find a 90% confidence interval for the mean number of polyester microfibers per 250 mL of beach sediment.Round your answers to two decimal places.The 90% confidence interval isto(b) What is the margin of error?Round your answer to two decimal places.margin of error =the absolute tolerance is +/-0.05I Privacy Policy I 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons. Inc.Version 4.24.20.1MacBook ProTheI'm**%232$&*234aice6.8.6.%3DdeleteRT.YU-DF GJK..returnCM.mmandMOSISOcommandoptionB.

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a) The provided sample mean is Xˉ=18.3\bar X = 18.3 and the sample standard deviation is s=8.2s =…

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(a) Find a 90% confidence interval for the mean number of polyester microfibers per 250 mL of beach sediment. Round your answers to two decimal places. The 90% confidence interval is to (b) What is the margin of error? Round your answer to two decimal places. margin of error = the absolute tolerance is +/-0.05

(a) Find a 90% confidence interval for the mean number of polyester microfibers per 250 mL of beach sediment. Round your answers to two decimal places. The 90% confidence interval is to (b) What is the margin of error? Round your answer to two decimal places. margin of error = the absolute tolerance is +/-0.05

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n Assighiment
DURCES
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ion 1-CI,
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(c) If we want a margin of error of only ±0.5 with 90% confidence, what sample size is needed?
tion 1-CI,
Round your answer up to the nearest integer.
tion 1-CI,
sample size =
ction 1-CI,
the absolute tolerance is +/-3
ection 1-CI,
Click if you would like to Show Work for this question: Open Show Work
ection 1-CI.
ection 1-D,
Section 1-D,
By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instruci
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MacBook Pro
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Assignment
Gradebook
ORION
Downloadable eTextbook
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PRINTER VERSION
1 BACK
NEXT
Chapter 6, Section 2-CI, Exercise 108
Plastic Microfiber Pollution on Shorelines
In a study, we see that plastic microparticles are contaminating the world's shorelines and that much of the pollution appears to come from fibers from washing polyester clothes. The same study also
took samples from ocean beaches. Five samples were taken from each of 18 different shorelines worldwide, for a total of 90 samples of size 250 mL. The mean number of plastic microparticles found
per 250 mL of sediment was 18.3 with a standard deviation of 8.2.
(a) Find a 90% confidence interval for the mean number of polyester microfibers per 250 mL of beach sediment.
Round your answers to two decimal places.
The 90% confidence interval is
to
(b) What is the margin of error?
Round your answer to two decimal places.
margin of error =
the absolute tolerance is +/-0.05
I Privacy Policy I 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons. Inc.
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