A figure skater begins a spin with her arms extended. If her arms are essentially a rod of length 1.65 m and mass 4.78 kg (1.e., both arms combined are one rod) and the rest of her body is a solid cylinder of mass 44.6 kg and radius 0.120 m, what is her moment of inertia at the start of the spin? 1.406 v kg m2 By pulling her arms in, the skater reduces the moment of inertia of her arms to 5.36 x 10- kg m2. what is the total moment of Inertia of the skater's arms and body in this new position? 1.35 x kg m2 If the skater begins her spin at 2.00 rev/s, what is her initial angular momentum? (Hint: Convert the angular velocity to rad/s before calculating angular momentum.) 13.63 x kg m/s Assuming that the external torque on the spinning skater is negligible, what is her angular momentum after pulling in her arms? 13.63 x kg m/s How fast is the skater spinning after she pulls in her arms? Give your answer both in rad/s and rev/s. x rad/s x rev/s 10 2.08 How much work must the skater do to pull in her arms? 39.75 How much work must the skater do to stop her spin at the end? 67.5
A figure skater begins a spin with her arms extended. If her arms are essentially a rod of length 1.65 m and mass 4.78 kg (1.e., both arms combined are one rod) and the rest of her body is a solid cylinder of mass 44.6 kg and radius 0.120 m, what is her moment of inertia at the start of the spin? 1.406 v kg m2 By pulling her arms in, the skater reduces the moment of inertia of her arms to 5.36 x 10- kg m2. what is the total moment of Inertia of the skater's arms and body in this new position? 1.35 x kg m2 If the skater begins her spin at 2.00 rev/s, what is her initial angular momentum? (Hint: Convert the angular velocity to rad/s before calculating angular momentum.) 13.63 x kg m/s Assuming that the external torque on the spinning skater is negligible, what is her angular momentum after pulling in her arms? 13.63 x kg m/s How fast is the skater spinning after she pulls in her arms? Give your answer both in rad/s and rev/s. x rad/s x rev/s 10 2.08 How much work must the skater do to pull in her arms? 39.75 How much work must the skater do to stop her spin at the end? 67.5
Related questions
Question
10
Transcribed Image Text:A figure skater begins a spin with her arms extended. If her arms are essentially a rod of length 1.65 m and mass 4.78 kg (i.e.,
both arms combined are one rod) and the rest of her body is a solid cylinder of mass 44.6 kg and radius 0.120 m, what is her
moment of inertia at the start of the spin?
kg m?
1.406
By pulling her arms in, the skater reduces the moment of inertia of her arms to 5.36 x 10-2 kg m2. what is the total moment of
Inertia of the skater's arms and body in this new position?
x kg m2
1.35
If the skater begins her spin at 2.00 rev/s, what is her initial angular momentum? (Hint: Convert the angular velocity to rad/s
before calculating angular momentum.)
13.63
x kg m2/s
Assuming that the external torque on the spinning skater is negligible, what is her angular momentum after pulling in her arms?
13.63
)× kg m2/s
How fast is the skater spinning after she pulls in her arms? Give your answer both in rad/s and rev/s.
x rad/s
x rev/s
10
2.08
How much work must the skater do to pull in her arms?
39.75
How much work must the skater do to stop her spin at the end?
67.5
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 5 steps with 5 images
