A Ferris wheel has a radius of 30 m. Its center is 31 m above the ground. It rotates once every 40 s. Suppose you get on the bottom at t = 0. Write an equation that expresses your height as a function of elapsed time. (t - 40) 40 Oh = 31 cos 2π- Oh 30 cos 2T- Oh = (t - 20) 40 Oh (t - 20) 40 31 cos 2T- (t - 20) 40 = 30 cos 2T- + 30 +1 +30 +31
A Ferris wheel has a radius of 30 m. Its center is 31 m above the ground. It rotates once every 40 s. Suppose you get on the bottom at t = 0. Write an equation that expresses your height as a function of elapsed time. (t - 40) 40 Oh = 31 cos 2π- Oh 30 cos 2T- Oh = (t - 20) 40 Oh (t - 20) 40 31 cos 2T- (t - 20) 40 = 30 cos 2T- + 30 +1 +30 +31
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question

Transcribed Image Text:A Ferris wheel has a radius of 30 m. Its center is 31 m above the ground.
It rotates once every 40 s. Suppose you get on the bottom at t = 0.
Write an equation that expresses your height as a function of elapsed time.
Oh = 31 cos 2T-
-
O h = 30 cos 2T
(t - 40)
40
=
(t - 20)
40
Oh 31 cos 2T-
=
(t - 20)
40
(t – 20)
40
Oh 30 cos 2π-
2T
+30
+1
+30
+31
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