A Ferris wheel has a diameter of 40 meters and rotates at a constant speed completing one full revolution every 2 minutes. If a person gets on the Ferris wheel at the bottommost point, express the person's height above the ground as a function of time, assuming the center of the Ferris wheel is at ground level.
A Ferris wheel has a diameter of 40 meters and rotates at a constant speed completing one full revolution every 2 minutes. If a person gets on the Ferris wheel at the bottommost point, express the person's height above the ground as a function of time, assuming the center of the Ferris wheel is at ground level.
Answer: The Ferris wheel has a diameter of 40 meters, which means the radius (r) is half of the diameter, i.e., (r = 20) meters. The Ferris wheel completes one full revolution every 2 minutes. The period (T) of the Ferris wheel is the time it takes to complete one full revolution. In this case, T = 2 minutes. The angular frequency (w) can be calculated using the formula (w = 2/?). Substituting the given value for (T): w = 2/? = ? radians per minute. Now, the height (h) of the person above the ground as a function of time (t) can be expressed using a sine function. The general form of a sine function is h(t) = A sin(wt+ϕ)+C where: - A is the amplitude (half the range of the function), - w is the angular frequency, - ϕ is the phase shift, - C is the vertical shift. In this case, since the person starts at the bottommost point, there is no phase shift (ϕ = 0), and the vertical shift (C) is equal to the radius of the Ferris wheel (20) meters). So, the height function is h(t) = 20 sin (?t) +20
- using this question and answer make a labeled diagram of the ferris wheel and make a visual answer ( explain with hand drawn images on whats going on )


Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 6 images









