A favorite demonstration among chemistry instructors, to show that the properties of a compound differ from those of its constituent elements, involves iron filings and powdered sulfur. If the instructor takes samples of iron and sulfur and just mixes them together, the two elements can be separated from one another with a magnet (iron is attracted to a magnet, sulfur is not). If the instructor then combines and heats the mixture of iron and sulfur, a reaction takes place and the elements combine to form iron (II) sulfide (which is not attracted by a magnet). Fe(s) + S(s) → FeS(s) Suppose 6.73 g of iron filings is combined with 18.4 g of sulfur. What is the theoretical yield of iron (II) sulfide? If the reaction formed 7.35 g of iron (II) sulfide, what is the percent yield? Molar Mass: Fe: 55.85 g/mol S: 32.07 g/mol
A favorite demonstration among chemistry instructors, to show that the properties of a compound differ from those of its constituent elements, involves iron filings and powdered sulfur. If the instructor takes samples of iron and sulfur and just mixes them together, the two elements can be separated from one another with a magnet (iron is attracted to a magnet, sulfur is not). If the instructor then combines and heats the mixture of iron and sulfur, a reaction takes place and the elements combine to form iron (II) sulfide (which is not attracted by a magnet).
Fe(s) + S(s) → FeS(s)
Suppose 6.73 g of iron filings is combined with 18.4 g of sulfur.
- What is the theoretical yield of iron (II) sulfide?
- If the reaction formed 7.35 g of iron (II) sulfide, what is the percent yield?
Molar Mass:
Fe: 55.85 g/mol
S: 32.07 g/mol
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