A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number.

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Student Number: 1700123
A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal
b)
voltages throughout the network are of 1 p.u. and the impedance of the electric
arc is neglected. Sequence impedance parameters of the generator,
transmission lines, and transformer are given in Figure Q3, where X and Y are
the last two digits of your student number.
jX2) = j0.2Y p.u. V=120° p.u.
jX22) = j0.2Y p.u.
jX2(0) = j0.3X p.u.
%3D
V =
= 1Z0° p.u.
V, = 120° p.u.
V3 = 120° p.u.
jXa1) = j0.1Y p.u.
jX«2) = j0.1Y p.u.
jX a0) = j0.1X p.u.
jX11(1) = j0.2 p.u.
1 jXn2) = j0.2 p.u. 2 A
jX1(0) = j0.25 p.u.
3
jXT(1) = j0.1X p.u. jXB1) = j0.1Y p.u.
jXr2) = j0.1X p.u. jXB(2) = j0.1Y p.u.
jXT0) = j0.1X p.u. jX3(0) = j0.15 p.u.
%3D
%3D
%3D
%3D
%3D
Figure Q3. Circuit for problem 3b).
For example, if your student number is c1700123, then:
jXa(1) = j0.13 p.u., jXa(2) = j0.13 p. u., and jXaco) = j0.12 p. u.
(i) Assuming a balanced excitation, draw the positive, negative and zero
sequence Thévenin equivalent circuits as seen from bus 4.
(ii)
Determine the positive sequence fault current for the case when a three-
phase-to-ground fault occurs at bus 4 of the network.
(iii) Determine the short-circuit fault current for the case when a one-phase-
to-ground fault occurs at bus 4.
(iv) Determine the short-circuit fault current for the case when a phase-to-
phase fault occurs at bus 4.
Transcribed Image Text:A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal b) voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jX2) = j0.2Y p.u. V=120° p.u. jX22) = j0.2Y p.u. jX2(0) = j0.3X p.u. %3D V = = 1Z0° p.u. V, = 120° p.u. V3 = 120° p.u. jXa1) = j0.1Y p.u. jX«2) = j0.1Y p.u. jX a0) = j0.1X p.u. jX11(1) = j0.2 p.u. 1 jXn2) = j0.2 p.u. 2 A jX1(0) = j0.25 p.u. 3 jXT(1) = j0.1X p.u. jXB1) = j0.1Y p.u. jXr2) = j0.1X p.u. jXB(2) = j0.1Y p.u. jXT0) = j0.1X p.u. jX3(0) = j0.15 p.u. %3D %3D %3D %3D %3D Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(1) = j0.13 p.u., jXa(2) = j0.13 p. u., and jXaco) = j0.12 p. u. (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 4. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 4 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus 4. (iv) Determine the short-circuit fault current for the case when a phase-to- phase fault occurs at bus 4.
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