A farmer wishes to estimate the average height of mango trees in his farm. He wants to be 99% confident that the estimate is accurate within 2 feet. How many samples snoula he takeif he knew that the standard deviation of heights measured was 4.38 feet? A. at most 31 B. at least 31 C. at most 32 D. at least 32 5. What is the margin of error for the estimation of proportion given that p=0.d,- 400 and confidence level of 0.90? A. 0.0358 B. 0.0376 C. 0.0478 D. 0.0449 For number 6-9: In a recent study of 35 Grade 3 pupils, the mean number of hours per week that they played video games was 16.6. The standard deviation of the population was 2.8. 6. Which of these is the point estimator? A. 2.8 C. 35 B. 16.6 D 40

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Nii. 4 &5
A farmer wishes to estimate the average height of mango trees in his farm. He wants to
be 99% confident that the estimate is accurate within 2 feet. How many samples shoua
he takeif he knew that the standard deviation of heights measured was 4.38 leet?
stimator.
n can be
A. at most 31
C. at most 32
D. at least 32
B. at least 31
5. What is the margin of error for the estimation of proportion given that p=0.7, n=
400 and confidence level of 0.90?
degrees
end the
A. 0.0358
C. 0.0478
D. 0.0449
B. 0.0376
mean
For number 6-9: In a recent study of 35 Grade 3 pupils, the mean number of hours per week that
they played video games was 16.6. The standard deviation of the population was 2.8.
tion
6.
Which of these is the point estimator?
A. 2.8
C. 35
D. 40
5
nterval.
В. 16.6
7. Determine the standard error
A. 0.47
С. 16.6
В. 2.8
D. 35
punces.
ces. In
8.
Find the values of the z-score at 95% confidence level for the estimated interval of the
population mean.
C. ±2.54
A. ±1.64
D. ±3.96
B. ±1.96
= 24.5,
9. Determine the confidence interval of the mean time in playing video games.
A. 15.4<p< 17.8
B. 15.7 <p< 17.5
C. 17.4<p<19.8
D. 7.4 <µ< 17.8
A recent survey of 8 social networking has a mean of 13.1 million visitors for a specific
10.
month with the standard deviation was 4.l million. Construct a 95% confidence
te the
Interval of the true mean.
A. 7.70<p<14.5
B. 9.70 <p< 16.5
C. 6.4<p<16.4
D. 5.4 <p< 17.8
Transcribed Image Text:A farmer wishes to estimate the average height of mango trees in his farm. He wants to be 99% confident that the estimate is accurate within 2 feet. How many samples shoua he takeif he knew that the standard deviation of heights measured was 4.38 leet? stimator. n can be A. at most 31 C. at most 32 D. at least 32 B. at least 31 5. What is the margin of error for the estimation of proportion given that p=0.7, n= 400 and confidence level of 0.90? degrees end the A. 0.0358 C. 0.0478 D. 0.0449 B. 0.0376 mean For number 6-9: In a recent study of 35 Grade 3 pupils, the mean number of hours per week that they played video games was 16.6. The standard deviation of the population was 2.8. tion 6. Which of these is the point estimator? A. 2.8 C. 35 D. 40 5 nterval. В. 16.6 7. Determine the standard error A. 0.47 С. 16.6 В. 2.8 D. 35 punces. ces. In 8. Find the values of the z-score at 95% confidence level for the estimated interval of the population mean. C. ±2.54 A. ±1.64 D. ±3.96 B. ±1.96 = 24.5, 9. Determine the confidence interval of the mean time in playing video games. A. 15.4<p< 17.8 B. 15.7 <p< 17.5 C. 17.4<p<19.8 D. 7.4 <µ< 17.8 A recent survey of 8 social networking has a mean of 13.1 million visitors for a specific 10. month with the standard deviation was 4.l million. Construct a 95% confidence te the Interval of the true mean. A. 7.70<p<14.5 B. 9.70 <p< 16.5 C. 6.4<p<16.4 D. 5.4 <p< 17.8
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