A- Express the concentration (given for water solutions) in ppm, molarity, and molality: 1.36 10 moles (NaHCO,) per liter. (The atomic weight of Na-23,C=12,0-16, H-1). B- A stock solution of dye with concentration of 150 ppm. How it can do to get the dye solution with concentration of 25 ppm in 150 ml . C- State the methods of expressing the composition of solutions, and then prove that

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Chapter7: Solutions And Colloids
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A- Express the concentration (given for water solutions) in ppm, molarity, and molality:
1.36*10° moles (NaHCO;) per liter . (The atomic weight of Na=23 , C-12,0-16,
H-1).
B- A stock solution of dye with concentration of 150 ppm. How it can do to get the dye
solution with concentration of 25 ppm in 150 ml.
C- State the methods of expressing the composition of solutions, and then prove that
ppm=mg/l.
Transcribed Image Text:A- Express the concentration (given for water solutions) in ppm, molarity, and molality: 1.36*10° moles (NaHCO;) per liter . (The atomic weight of Na=23 , C-12,0-16, H-1). B- A stock solution of dye with concentration of 150 ppm. How it can do to get the dye solution with concentration of 25 ppm in 150 ml. C- State the methods of expressing the composition of solutions, and then prove that ppm=mg/l.
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