a) Explain the phenomena of supersaturation and nucleation in crystallization and explain three (3) methods to form supersaturation and recommend the appropriate equipment for each of them.  b) A hot solution of 1500 kg containing 45 wt% of CuS04 and water is cooled to 278 K and formed a precipitation of CuSOc5H20 crystals. The solubility of the anhydrous CuS04 at 278 K is 20.5 wt% in the solution. If 5wt% of the original water evaporates, with a proper schematic diagram shows the inlet and outlet streams and calculate the yield of the crystal obtained. Given the molecular weight of CuS04 = 159.609 g/mol and CuS04•5H20 = 294.72 g/mol.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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a) Explain the phenomena of supersaturation and nucleation in crystallization and explain three (3) methods to form supersaturation and recommend the appropriate equipment for each of them. 

b) A hot solution of 1500 kg containing 45 wt% of CuS04 and water is cooled to 278 K and formed a precipitation of CuSOc5H20 crystals. The solubility of the anhydrous CuS04 at 278 K is 20.5 wt% in the solution. If 5wt% of the original water evaporates, with a proper schematic diagram shows the inlet and outlet streams and calculate the yield of the crystal obtained. Given the molecular weight of CuS04 = 159.609 g/mol and CuS04•5H20 = 294.72 g/mol.

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