Neelesh Pant is the production manager for Citrus Groves Inc., located just north of Ranikhet,Uttarakhand. Neelesh is concerned that the last 3 years' late freezes have damaged the 2,500orange trees that Citrus Groves owns. In order to determine the extent of damage to the trees,Neelesh has sampled the number of oranges produced per tree for 42 trees and found that theaverage production was 525 oranges per tree and the standard deviation was 30 oranges per tree.(a) Estimate the population standard deviation from the sample standard deviation.(b) Estimate the standard error of the mean for this finite population.(c) Construct a 98 percent confidence interval for the mean per-tree output of all 2,500 trees.(d) If the mean orange output per tree was 600 oranges 5 years ago, what can Neelesh sayabout the possible existence of damage now?

As per our guidelines, we are allowed to answer first three sub-parts . Thanks Sample size , n =…

(a) Estimate the population standard deviation from the sample standard deviation. (b) Estimate the standard error of the mean for this finite population. (c) Construct a 98 percent confidence interval for the mean per-tree output of all 2,500 trees.

(a) Estimate the population standard deviation from the sample standard deviation. (b) Estimate the standard error of the mean for this finite population. (c) Construct a 98 percent confidence interval for the mean per-tree output of all 2,500 trees.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Calculate the 95% confidence interval of the population mean, assuming that the population standard…

A: Assuming σ is unknown , 95% CI of populationmean is given as :Critical…

Q: When the standard deviation used to construct a confidence interval for a population mean increases,…

A: Given data: When the standard deviation used to construct a confidence interval for a population…

Q: Using a t-table or a t-score calculator, find the value of t for sample size (n) of 25 to estimate…

A: Sample size n=25

Q: Suppose that a random sample of sixteen recently sold houses in a certain city has a mean sales…

Q: Suppose that the number of students passed a Statistics class are normally distributed. A simple…

A: We have given that The number of students passed a Statistics class are normally distributed. A…

Q: From a random sample of 49 high school seniors, the sample mean and standard deviation of the math…

Q: The Human Resource Department (HRD) of a company developed an aptitude test for screening potential…

A: Solution: Given information: n= 13 Sample size x=96 Sample meanμ=100 Population means= 5.2 sample…

Q: A sample of thirty six (36) observations is taken from a normally distributed population with…

Q: Construct the indicated confidence interval for the difference between population proportions p1 -…

Q: A quality control manager wants to be sure that the standard deviation of oil containers is below a…

A: Let Xi be the amount of oil in the ith container,i=1,2,...,n.

Q: Compute for a 90% confidence interval estimate for µ=mean score in the reading comprehension test of…

Q: We take a sample of 50 people and obtain a sample mean of 147 pounds with a standard deviation of 15…

A: We have given that Sample size n = 50 Sample mean = 147 Standard deviation = 15 90%confidence…

Q: Suppose you use simple random sampling to select and measure 47 dogs' weights, and find they have a…

A: Given, mean is 78 and standard deviation is 13.5. Sample number is 47. We with use one sample z…

Q: 49 items are randomly selected from a population of 500 items. The sample mean is 40 and the sample…

A: Confidence interval can be calculated using this formula:CI = x̄ + t nswhere:x̄ = sample mean =…

Q: The quality-control manager of a chemical company randomly sampled twenty 100-pound bags of…

A: It is given that the sample variance is 6.62 and the sample size is 20.

Q: In a random sample of 12 people, the mean commute time to work was 30 minutes and the sample…

Q: Construct the indicated confidence interval for the difference between population proportions p1-p2.…

Q: When planning to construct a 95% confidence interval for a population mean such that it is within…

A: Given data, E=1/8=0.125 Let p=0.5 z-value at 95% confidence is Zc=1.96 n=?

Q: Construct a 90% Confidence Interval for the population mean u

A: Given that the sample size is n = 36 Sample mean = 106 Population SD = 12 At 90% confidence level,…

Q: A random sample of 25 business students required an average of 50.7 minutes to complete a statistics…

A: Given that, Mean = 50.7 Standard deviation = 10.4 Sample size = 25

Q: The annual earnings (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: Given information: The annual earnings (in dollars) of n = 35 randomly selected microbiologists are…

Q: From a random sample of 64 high school seniors, the sample mean and standard deviation of the math…

Q: Forty-two items are randomly selected from a population of 500 items. The sample mean is 40 and the…

A: Given : Population size (N) = 500 Sample size (n) = 42 Sample Mean (μ) = 40 Sample standard…

Q: Find 80%, 85% and 99.9% confidence interval for the sample mean of a pouplation, if we know that in…

A: Given information: Sample mean=60 Standard deviation =5 Sample size=70

Q: company manufactures a certain over-the-counter drug. The company samples 80 pills and finds that…

A: We have given that Sample size n = 80 Sample mean = 325.5 Standard deviation s=10.3 90%confidence…

Q: The pH of rain, measured at a weather station in Michigan, was observed for 39 consecutive rain…

Q: for a sample of 57 that has a mean of 6200 and a standard deviation of 254, calculate the 95%…

Q: or a sample of 121 that has a mean of 6540 and a standard deviation of 780, calculate the 90%…

Q: Suppose average pizza delivery times are normally distributed with an unknown population mean and a…

A: The provided information is:

Q: Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.t Suppose a small…

A: The known values are, Critical values: Using the z-table, the critical value at 80% confidence…

Q: Find the critical value for a 94% confidence interval when the sample size is 51 and the population…

A: Given Level of significance ɑ=0.06 , n=51 Population standard deviations σ known

Q: A small business wanted to estimate the mean income from their customers. They took a sample of 256…

A: We have to find the 90% confidence interval estimate for the population mean income of their…

Q: Assume that you have a normally distributed variable with known standard variance. How many standard…

A: We have given a normally distributed variable with known standard variance.Confidence level (c) =…

Q: A sample of 28 elements is selected to estimate a 95% confidence interval for the variance of the…

A: We have given that sample size=n=28 95% confidence interval for variance

Q: mple of size 50 from a normal distribution has sample mean 5 and sample variance 20. Find 96%…

A: n=50sample mean =5sample variance =20comfidence interval=0.96we have to find out the 96% confidence…

Q: A sample from a normal population is given with mean 54 and the standard deviation 12. Find the…

A: Given : n = 25 x¯=54 S = 12

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Neelesh Pant is the production manager for Citrus Groves Inc., located just north of Ranikhet,
Uttarakhand. Neelesh is concerned that the last 3 years' late freezes have damaged the 2,500
orange trees that Citrus Groves owns. In order to determine the extent of damage to the trees,
Neelesh has sampled the number of oranges produced per tree for 42 trees and found that the
average production was 525 oranges per tree and the standard deviation was 30 oranges per tree.
(a) Estimate the population standard deviation from the sample standard deviation.
(b) Estimate the standard error of the mean for this finite population.
(c) Construct a 98 percent confidence interval for the mean per-tree output of all 2,500 trees.
(d) If the mean orange output per tree was 600 oranges 5 years ago, what can Neelesh say
about the possible existence of damage now?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

The mean and standard deviation of the quality grade points of a random sample of 36 students from a large population are 2.6 and 0.3 respectively. The 99% confidence interval for the mean of the entire population is
Obtain the confidence limits for the ratio of variances of two normal populations.
The sample mean and standard deviation for weights of 100 boxes are 12.05g and 0.1g respectively. Find a 90% confidence interval for the mean weight of the boxes.
In constructing a 98% confidence interval for the mean of a population with variance 25, how large a sample must be used to ensure that the margin of error does not exceed 0.8? Calculation.
In a random sample of 5 mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results.
In a random sample of 17 people, the mean commute time to work was 30.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t- distribution to construct a 95% confidence interval for the population mean y. What is the margin of error of y? Interpret the results.
Estimate the minimum sample size needed to achieve the margin of error E=0.013 for a 95% confidence interval.
A sample of 20 cows is drawn to estimate the mean weight of a large herd of cattle. If the standard deviation of the sample is 96 kg, what is the margin of error in a 90% confidence interval estimate?
A sample of 18 items provides a sample standard deviation of 6.(A). Compute the 90% confidence interval estimate of the population standard deviation. (B). Compute the 95% confidence interval estimate of the population variance.
Use the order statistics approach to estimate a 90% confidence interval of 95.1% VaR for a sample size of n = 1000 observations drawn from a normal distribution with zero mean and variance one.
need help solving also find the test statistic find the p value