(A) Estimate the area under the graph of f(x) = 2x' + 3 %3D from x = -1 to x = 4, first using 5 approximating rectangles and right endpoints, and then improving your estimate using 10 approximating rectangles and right endpoints. 5 Rectangles = 10 Rectangles = (B) Repeat part (A) using left endpoints. 5 Rectangles = 10 Rectangles = (C) Repeat part (A) using midpoints. 5 Rectangles = 10 Rectangles =

Q: Find the exact area between the graphs of y = x^3 + 7 and y = -x + 7 for 0

A: Area under the curve y1 and y2 is given by A = ∫( y2 - y1 )dx

Q: Sketch a graph of y = 8 on [- 5, 4] and use geometry to find the exact value of int -5 ^ 4 8 dx.

A:

Q: f(x) = x^3 + 4x and g(x) = 6x^2 - x Find the area between the two curves

A: We have to find the area between the given curves.

Q: Explain how to compute the area between the curve y=x^3-x^2-3x+3 and the x-axis from the values x=-2…

A: Let's draw the curves : Red shows curve of x3-x2-3x+3 .Blue shows curve of x =-2 .Green shows curve…

Q: Find the area under y = x(e)^(-x)^(2) for x > 1

A: The given curve y=xe-x2 We have to find the area under the curve for x>1.

Q: F(x)=195(.806)^x how do particular region where X is the year and X=0 corresponds to 1962 estimate…

A: Given function  F( x ) = 195( 0.806 )x where x is the year  x =0 corresponds to 1962

Q: Approximate the area under the graph of F(x)=0.6x^(3)+6x^(2)-0.6x-6 over the interval [-6,-1] using…

A: According to the given data we derived below.

Q: Calculate the area between x=y+3 ,x=y^2 from y=-1 to y=1 7/3 18/7 32/6

A:

Q: area is given by the function x^0.5+y^0.5=1

A: We have to find the area of given function.

Q: Find area between the curves y=17/(9+x^2) and y=13/(1+x^2)

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Q: Estimate the area under the graph of f(x)= 7 +4x^2 from x = -1 to x = 2 using both three rectangles…

A: All the Riemann sum are given as follows:

Q: Find the area under the graph of y = (x + 1)^-2for x ≥ 0.

A:

Q: Solve the area bounded by the curve x=y^2 and the line y=x+1, y=2, and y=-2. Graph manually.

A:

Q: Find the area under the curve  y= (2x2 - 7) / (sqrt(x)) ,   16 <= x <= 20

A:

Q: Can you explain how I can find the area of y=1/x^3/2, x=4, the x-axis to the right, and y=x^-4/3, x…

A: Region is bounded by y=1x3/2,y=1x4/3,x=4,x=8