A dry natural gas reservoir has the following given data: Component Componenemole fraction Methane 0.8612 Ethane 0.0591 Propane 0.0358 Butane 0.0172 Pentanes 0.005 Co2 0.001 N2 0.0107 H2S 0.01 If this natural gas is going to flow in a vertical pipe with an I.D of 0.3 ft at a gas flow rate of 1000 cu ft/day. Is the flow in the pipe to be laminar or turbulent at an average pressure of 1500 psi and an average temp of 100 F? NRe = 2.2 - 10-2 %3D Carr-Kobayashl-Burrows Correction Tre= Tpe - 80 yco, + 130 yu2s - 250 yn2 Pe = Ppe + 440 yco, + 600 yus- 170 yN2

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Question #1
A dry natural gas reservoir has the following given data:
Component
Componenemole fraction
Methane
0.8612
Ethane
0.0591
Propane
0.0358
Butane
0.0172
Pentanes
0.005
Co2
0.001
N2
0.0107
H2S
0.01
If this natural gas is going to flow in a vertical pipe with an I.D of 0.3 ft at a gas flow rate of 1000
cu ft/day. Is the flow in the pipe to be laminar or turbulent at an average pressure of 1500 psi
and an average temp of 100 F?
NRe = 2.2 10-2
Carr-Kobayashi-Burrows Correction
Tpe =Tpe- 80 yco2
+ 130 yus - 250 yN2
Ppe = Ppe + 440 yco, + 600 yH2s- 170 yn2
Transcribed Image Text:Question #1 A dry natural gas reservoir has the following given data: Component Componenemole fraction Methane 0.8612 Ethane 0.0591 Propane 0.0358 Butane 0.0172 Pentanes 0.005 Co2 0.001 N2 0.0107 H2S 0.01 If this natural gas is going to flow in a vertical pipe with an I.D of 0.3 ft at a gas flow rate of 1000 cu ft/day. Is the flow in the pipe to be laminar or turbulent at an average pressure of 1500 psi and an average temp of 100 F? NRe = 2.2 10-2 Carr-Kobayashi-Burrows Correction Tpe =Tpe- 80 yco2 + 130 yus - 250 yN2 Ppe = Ppe + 440 yco, + 600 yH2s- 170 yn2
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