A drug manufacturer claims that a new drug lowers cholesterol level in patient studied. The following data shows the levels of cholesterol in 5 patients before and after taking the drug. Assume the data is normally distributed. Is there enough evidence to support the claim at a 0.02 level of significance? Complete the table, then find the standard deviation of the difference sd 3 4. 5 First Attempt 209 234 203 230 212 Second Attempt 207 228 200 218 201 Difference d Mean d (d – d)? Standard Deviation t-Test Statistic Degrees of Freedom =(P-P)3 (%23) Prf - P n-1 Sa = n - 1 Round all values to 3 decimal places a. The standard deviation s = b. t test statistic = C. At the 0.02 level, the critical value t
A drug manufacturer claims that a new drug lowers cholesterol level in patient studied. The following data shows the levels of cholesterol in 5 patients before and after taking the drug. Assume the data is normally distributed. Is there enough evidence to support the claim at a 0.02 level of significance? Complete the table, then find the standard deviation of the difference sd 3 4. 5 First Attempt 209 234 203 230 212 Second Attempt 207 228 200 218 201 Difference d Mean d (d – d)? Standard Deviation t-Test Statistic Degrees of Freedom =(P-P)3 (%23) Prf - P n-1 Sa = n - 1 Round all values to 3 decimal places a. The standard deviation s = b. t test statistic = C. At the 0.02 level, the critical value t
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Transcribed Image Text:A drug manufacturer claims that a new drug lowers cholesterol level in patient studied. The following data
shows the levels of cholesterol in 5 patients before and after taking the drug. Assume the data is normally
distributed. Is there enough evidence to support the claim at a 0.02 level of significance?
Complete the table, then find the standard deviation of the difference sa
4.
5
First Attempt
209
234
203
230
212
Second Attempt
207
228
200
218
201
Difference d
Mean d
¿(P - P)
Standard Deviation
t-Test Statistic Degrees of Freedom
=1 (P-P)3
(2)
n-1
n - 1
Round all values to 3 decimal places
a. The standard deviation sa =
b. t test statistic =
C. At the 0.02 level, the critical value t =
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