A drug company is considering marketing a new local anesthetic. The effactive time of the anesthetic the drug company is currently producing has a normal distribution with an mean of 7.4 minutes with a standard deviation of 1.2 minutes. The chemistry of the new anesthetic is such that the effective time should be nomaly distributed with the same standard deviation, but the mean effective time may be lower. If it is lower, the drug company will market the new anesthetic; otherwise, they will continue to produce the older one. A sample of size 36 results in a sample mean of 7.1. A hypothesis test will be done at the 10% level of significance to help make the decision. v Slap 1: The nu hypolhasis is Ho: 1. -7.4 Slap 1: The altemative hypothesis is H Step 2. The value of the test statistics is Step 3: The lower critical value is 2 P27.4 1. PS7.4 4 H7.4 Note: If there is one critical value, one of the "lower critical value" or upper critical value" should be "none". v Step 3. The upper critical value is S. p>7.4 Note: f there is one critical value, one of the "lower critical value upper critical valuue" should be "none 6. U<7,4 7. 1.50 Slap 3 The pvalue in &1.28 9. 0.0668 Step 4 You should 10.1.28 Step 6: Your should conciude that 11.1.60 12. not reject Ho 13. reject Ho 14.none 15. there is ucient evidence that the mean efective time is minutes than 7.4 16. there ia not suficient evidence that the mean effective time is less than 74 minutes 17. here is suffcient evidence that the mean effective time i not less than 74 minutes 50 18. there is not sufficient evidence that the mean effective time is not less than 74 minutes ud
A drug company is considering marketing a new local anesthetic. The effactive time of the anesthetic the drug company is currently producing has a normal distribution with an mean of 7.4 minutes with a standard deviation of 1.2 minutes. The chemistry of the new anesthetic is such that the effective time should be nomaly distributed with the same standard deviation, but the mean effective time may be lower. If it is lower, the drug company will market the new anesthetic; otherwise, they will continue to produce the older one. A sample of size 36 results in a sample mean of 7.1. A hypothesis test will be done at the 10% level of significance to help make the decision. v Slap 1: The nu hypolhasis is Ho: 1. -7.4 Slap 1: The altemative hypothesis is H Step 2. The value of the test statistics is Step 3: The lower critical value is 2 P27.4 1. PS7.4 4 H7.4 Note: If there is one critical value, one of the "lower critical value" or upper critical value" should be "none". v Step 3. The upper critical value is S. p>7.4 Note: f there is one critical value, one of the "lower critical value upper critical valuue" should be "none 6. U<7,4 7. 1.50 Slap 3 The pvalue in &1.28 9. 0.0668 Step 4 You should 10.1.28 Step 6: Your should conciude that 11.1.60 12. not reject Ho 13. reject Ho 14.none 15. there is ucient evidence that the mean efective time is minutes than 7.4 16. there ia not suficient evidence that the mean effective time is less than 74 minutes 17. here is suffcient evidence that the mean effective time i not less than 74 minutes 50 18. there is not sufficient evidence that the mean effective time is not less than 74 minutes ud
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is currently
producing has a nomal distribution with an mean of 7.4 minutes with a standard deviation of 1.2 minutes. The chemistry of the new
anesthetic is such that the effective time should be normally distributed with the same standard deviation, but the mean effective time
may be lower. If it is lower, the drug company will market the new anesthetic; otherwise, they will continue to produce the older one. A
sample of size 36 results in a sample mean of 7.1. A hypothesis test will be done at the 10% level of significance to help make the
decision.
v Step 1: The nul hypothesis is Ho:
Stap 1: The altemative hypothesis is H:
1. p-7.4
2 P27.4
Step 2 The value of the test statistics is
3. US7.4
Step 3: The lower critical value is
Note: If there is one critical value, one of the "lower critical value" or
upper critical value" should be "none".
Step 3. The upper critical value is
4 H7.4
5. p>7.4
Note: If there is one critical value, one of the "ower critical value" or
"upper critical value" should be "none
6. U<7,4
7. -1.50
& -1.28
9. 0.0668
v Stap 3 The p-value is
Step 4 You should
10.1.28
Step 5: Your should conclude that
11.1.60
12. not reject Ho
13. reject Ho
14. none
15. there is suffcient evidence that the mean effective time is less than 74
minutes
16. there is not suficient evidence that the mean effective time is less than 7.4
minutes
17.there is suficient evidence that the mean effective time is not less than 74
minutes
50
18. there is not sufficient evidence that the mean effective time is not less than
74 minutes
ue
lue
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