(a) Draw an event tree and show on the event tree all the probabilities in branch points.
Q: Suppose that a nite class contains 50% freshmen, 15% sophomores, 10% juniors, and the rest seniors.…
A: Tree diagram:
Q: (a) Draw a tree diagram to illustrate all the possible outcomes and associated probabilities. State…
A: here define event R = red card G= Green card B= Blue card
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A: Given, P(A) = 0.43 P( A or B) = 0.87 Since events, A and B are mutually exclusive events P(A and B)…
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A: Mutually exclusive events : An events which can not occur at same time is called mutually exclusive…
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A: From the provided information, P (B) = 0.224 and P (A U B) = 0.673 The events A and B are mutually…
Q: Suppose that A and B are mutually exclusive events such that P(A) = 0.25 and P(B) = 0.40. Determine…
A: Special Addition Rule:
Q: If A and B are not mutually exclusive events and P(A) = 0.60 and P(B) = 0.80, then find P(AUB)
A: Given A and B are not mutually exclusive events And P(A) = 0.60 and P(B) = 0.80
Q: Draw a tree-diagram to represent all probabilities for the following. A bag contains 14 green and…
A: It is provided,Number of green marbles are 14.Number of orange marbles are 8.Total number of marbles…
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A:
Q: If a class has 8 freshmen, 5 sophomores, 4 juniors, and 2 seniors, what is the probabilitythat three…
A: Given: 8 freshmen 5 sophomores 4 juniors 2 seniors Total = 8+5+4+2=19
Q: In an examination, Allen has to choose two correct statements from a list of five statements for a…
A: (i) The tree diagram is given as
Q: Consider two disjoint or mutually exclusive events A and B. If P(A)=0.7 and P(B)=0.2 find P(A or B)
A: Given P(A)=0.7 and P(B)=0.2 A and B are mutually exclusive
Q: Assume that there are 15 cars: 10 Chevrolets, 4 Fords, and 1 Toyota. Two cars leave at random, one…
A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…
Q: The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given…
A: Given that P(A)=0.35, P(B) = 0.22, P(C)=0.18 P(A and B) 0.11, P(A and C)=0.03, P(B and C)=0.08 , P(A…
Q: Suppose that 4.5% of all adults over 50 have cancer. A certain physician correctly diagnoses 94% of…
A: Given , P(A) = 0.045 P(Ac) = 1- 0.045 = 0.955
Q: April has a bag with 7 blue sweets and 3 red sweets in it She picks up a sweet at random from the…
A: The number of blue sweets in the bagThe number of red sweets in the bagThe total number of sweets,
Q: the first student is a boy and the second student is a girl,
A:
Q: Assuming that every time you roll dice the events are independent of each other (meaning that one…
A:
Q: Suppose that C and D are mutually exclusive events such that P(C) = 0.14 and P(D) = 0.32. Determine…
A: Given, P(C) = 0.14 P(D) = 0.32 P(C or D)=?
Q: Suppose we define A as the event of obtaining {1, 3, 5}, and event B as the set {1,5,6}. (a) Are…
A: Solution:- Given that A = {1, 3, 5}, and event B ={1,5,6}. (a) A∩B={1,5} No, events A and B are…
Q: If P(A)= 0.6, P(B) = 0.5, P(AUB) =0.9, then A and B are mutually exclusive events. Select one: OTrue…
A: Given P(A)=0.6P(B)=0.5P(AUB)=0.9
Q: A magician appears to be using a biased coin during one of their magic tricks. To find out whether…
A: Given that: P(Head) = 3/8 =P(T) P(tail) = 5/8=P(H)
Q: he Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given by…
A: Given that P(A)=0.38, P(B) = 0.29, P(C)=0.12 P(A and B)=0.12, P(A and C)=0.04, P(B and C) = 0.06…
Q: The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given…
A: Given that P(A)=0.32, P(B)=0.24, P(C)=0.11 P(A and B)=0.13, P(A and C)=0.03, P(B and C)=0.08 P(A…
![A new vaccine against the coronavirus has been developed. The vaccine was tested on
10,000 volunteers and the study has shown that 65% of those tested do not get sick from the
coronavirus. Unfortunately, the vaccine has side effects and in the study it was shown that
the probability of getting side effects among those who did not get sick is 0.31, while the
probability of getting side effects among those who got sick from corona despite vaccination
is 0.15.
(a) Draw an event tree and show on the event tree all the probabilities in branch points.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8075515e-732c-4756-9368-4c5a08f4c849%2Fcda39b0b-e0f5-4556-8aba-0428732cd4c9%2Fktd1dy_processed.png&w=3840&q=75)
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- What is an experiment?What is meant by the sample space of an experiment?A new vaccine against the coronavirus has been developed. The vaccine was tested on 10,000 volunteers and the study has shown that 65% of those tested do not get sick from the coronavirus. Unfortunately, the vaccine has side effects and in the study it was shown that the probability of getting side effects among those who did not get sick is 0.31, while the probability of getting side effects among those who got sick from corona despite vaccination is 0.15.
- A new vaccine against the coronavirus has been developed. The vaccine was tested on10,000 volunteers and the study has shown that 65% of those tested do not get sick from thecoronavirus. Unfortunately, the vaccine has side effects and in the study it was shown thatthe probability of getting side effects among those who did not get sick is 0.31, while theprobability of getting side effects among those who got sick from corona despite vaccinationis 0.15. (b) What is the probability that a randomly vaccinated person does not become ill with thecoronavirus and does not get side effects? (c) What is the probability that a randomly vaccinated person gets side effects? (d) What is the probability that a randomly vaccinated person who has not experienced sideeffects does not become ill with the coronavirus?A new vaccine against the coronavirus has been developed. The vaccine was tested on10,000 volunteers and the study has shown that 65% of those tested do not get sick from thecoronavirus. Unfortunately, the vaccine has side effects and in the study it was shown thatthe probability of getting side effects among those who did not get sick is 0.31, while theprobability of getting side effects among those who got sick from corona despite vaccinationis 0.15. (c) What is the probability that a randomly vaccinated person gets side effects?(d) What is the probability that a randomly vaccinated person who has not experienced sideeffects does not become ill with the coronavirus?A new vaccine against the coronavirus has been developed. The vaccine was tested on10,000 volunteers and the study has shown that 65% of those tested do not get sick from thecoronavirus. Unfortunately, the vaccine has side effects and in the study it was shown thatthe probability of getting side effects among those who did not get sick is 0.31, while theprobability of getting side effects among those who got sick from corona despite vaccinationis 0.15. (a) Draw an event tree and show on the event tree all the probabilities in branch points. (b) What is the probability that a randomly vaccinated person does not become ill with thecoronavirus and does not get side effects?
- A health officer thinks that there is an association between diabetes (DM) and hypertension (HPT). He believes that those with DM are more likely to have HPT as well. For his research, from the hospital records, he selected a random sample of 400 patients, 300 with DM and 100 without DM. Out of the 300 DM patients, 60 had HPT as well and out of the 100 non DM patients 10 had HPT. He also recorded the patients’ gender. With the data, he performed two analyses, one for all policyholders and the other by gender. The following are some of the output from SPSS. Must the manager consider gender as well in this case? If yes, stating the evidence, explain why. If you are the health officer, how would the results above help you in making decision? What other variables, if any, should be considered as well?A health officer thinks that there is an association between diabetes (DM) and hypertension (HPT). He believes that those with DM are more likely to have HPT as well. For his research, from the hospital records, he selected a random sample of 400 patients, 300 with DM and 100 without DM. Out of the 300 DM patients, 60 had HPT as well and out of the 100 non DM patients 10 had HPT. He also recorded the patients’ gender. With the data, he performed two analyses, one for all policyholders and the other by gender. The following are some of the output from SPSS. State the percentage of DM and non DM patients who had State the test that was used in these Test if there is an association between DM and HPTLung cancer is the leading cause of cancer-related deaths in the United States. Researchers examined the idea of testing all Medical-enrolled heavy smokers for lung cancer with a computed tomography (CT) scan every year. In this population, the lifetime chance of developing lung cancer is high. In any given year, approximately 3% of heavy smokers develop lung cancer. The CT scan positively identifies lung cancer 89% of the time, and it gives a negative result for 93% of individuals who do not have lung cancer.
- The drug Prevnar is a vaccine meant to prevent bacterial meningitis. A randomized, double-blind clinical trial was conducted. A total of 551 people were surveyed. Where the subjects in Group 1 received Prevnar and the subjects in Group 2 received a control vaccine. 137 of 452 subjects in Group 1 and 31 of 99 subjects in Group 2 experienced drowsiness as a side effect. Can you conclude that there is a significant difference in the proportion of people in group 1 and group 2 experienced drowsiness as a side affect at the 1% significance level?At a sexually transmitted disease (STD) clinic in Miami, Florida, patients were screened for hepatitis C using Centers for Disease Control and Prevention (CDC) screening criteria in the form of a questionnaire (Weisbord et al., 2003). The study concluded that the probability of having Hepatitis C is Pr{disease} = 0.047, the probability that the test comes up positive for those that have Hepatitis C (sensitivity) is 0.61 and the probability it comes up negative for those that do not have Hepatitis C (specificity) is 0.91. What is the probability that the test comes up positive? (Do not round until the final answer. Round the final answer to 5 places after the decimal.) What is the probability of a false negative? (Do not round until the final answer. Round the final answer to 5 places after the decimal.) What is the probability of a false positive? (Do not round until your final answer. Round your final answer to 5 places after the decimal.) Given that the test comes up…new drug is being proposed for the treatment of migraine headaches. The FDA will not approve the new drug if it does not show a statistically significant improvement as compared to a placebo. In an experiment 40 people who suffer from migraine headaches receive the new drug and 18 of them report an improvement in their migraine pain (group 2). Another 40 people were place in the placebo group (group 1). Of these 13 reported an improvement in their migraine pain. Help the FDA, by forming a conclusion based on the following supporting statistical evidence. Sample Data Sample X N Sample Proportion Placebo (group 1) 13 40 0.325 New Drug (group 2) 18 40 0.450 Difference = p1 - p2 95% Confidence Interval for Difference p1-p2: (-0.337, 0.087) P-value = 0.247 The estimated difference between the placebo group and the new drug treatment group is -0.125. A. True B. False
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