(a) Draw a normal probability plot to determine if the data could have come from a nomal distribution. Choose the correct plot below. O A. O B. Oc. OD. 2.57 2.5 2.57 2.5 -2.5 1000 1300 1000 Observed value -2.6 1000 1300 1600 Ohserved value -2.5 1000 1300 Observed valun -2.61 1000 1300 1600 Observed value 1600 (b) Determine the mean and standard deviation of the sample data. The mean of the sample data is D. (Round to one decimal place as needed.) The standard deviation of the sample data is. (Round to one decimal place as needed.) (c) Using the sample mean and sample standard deviation obtained in part (b) as estimates for the population mean and population standard deviation, respectively, draw a graph of a normal model for the distribution of chips in a bag of cookies. O A. O B. Oc. OD. Observed value Observed value Observed value Observed value 900 1200 1500 1800 1000 1400 1800 2200 600 1000 1400 1800 900 1200 1500 1800

Q: 3 -4- -0- 4. 2.

A:

Q: 12 5(.8)0

A: We can solve given problem by using G.P series.

Q: 4 3/4 - 2 5/6

A: Given that the expression is

Q: sing the geometry of the graph ,evalvate the definite integrals.

A: As this is a multiple subpart question according to the Bartleby Answering rule, only first three…

Q: 9 b and c

A: b) We check if the denominator is 0 for any value of x.  2x2+5=0 2x2=-5 x2=-5/2 (not possible) So…

Q: 3/8+5/24

A: The given expression is 3/8 + 5/24.Simplify the given expression as follows.

Q: 4. Fill in the following contingency table with the number of observations that fall into each com-…

A: x1 = number of colored oranges from Skittles brand = 77 x2 = number of colored oranges from M &…

Q: 6/9 +  5/18 + 1 3/6

A:

Q: 38 10

A:

Q: 0218 X 17 (2) 600 x 38 131 784 X 44 (47664 X 18 157146X1

A: We need to perfrom multiplication.

Q: 6 3/20 - 6 3/8

A:

Q: 2.763-4.5(2.1x-5.1432)=6.32x+5

A:

Q: 5 2/5+ n= 75/6

A: Given query is to find the value of n.

Q: 8-8.2+5.0

A: