A double effect evaporator is used to concentrate an 18% CuSO4 solution. At the end of the evaporation, 1000 kg/h of 50% CuSO4 solution are obtained. If the water evaporated in the second effect is half the water evaporated in the first effect. Assume that the flow F2 is equal to the flow F6. Determine: a) The amount of solution fed in the first effect. b) The amount of water evaporated in the first and second effect. c) The amount of solution fed in the second effect, as well as its composition. F1 = 18% CUSO4 F2 F3 F4 F5=1000 kg/h F6-Condensed water

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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A double effect evaporator is used to concentrate an 18% CuSO4 solution. At the end of the
evaporation, 1000 kg/h of 50% CuSO4 solution are obtained. If the water evaporated in the second
effect is half the water evaporated in the first effect. Assume that the flow F2 is equal to the flow
F6. Determine:
a) The amount of solution fed in the first effect.
b) The amount of water evaporated in the first and second effect.
c) The amount of solution fed in the second effect, as well as its composition.
F1= 18% CuSO4
F2
F3
F4
F5=1000 Kg/h
F6-Condensed
water
Transcribed Image Text:A double effect evaporator is used to concentrate an 18% CuSO4 solution. At the end of the evaporation, 1000 kg/h of 50% CuSO4 solution are obtained. If the water evaporated in the second effect is half the water evaporated in the first effect. Assume that the flow F2 is equal to the flow F6. Determine: a) The amount of solution fed in the first effect. b) The amount of water evaporated in the first and second effect. c) The amount of solution fed in the second effect, as well as its composition. F1= 18% CuSO4 F2 F3 F4 F5=1000 Kg/h F6-Condensed water
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