a double angle_ Identity to Lind the exact cos x = - = // and II LALIT valve cos x = -5/55 4 tan (2x)= 11. Using CSC (2x)= Cos (2x)= sec (2x) Cot (2x)= sin (2x): = "
a double angle_ Identity to Lind the exact cos x = - = // and II LALIT valve cos x = -5/55 4 tan (2x)= 11. Using CSC (2x)= Cos (2x)= sec (2x) Cot (2x)= sin (2x): = "
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
Number 11
![7.
Use a
exact value of
sin (
-reference angle
3
12
8
Use a half angle identity → sinl
TT
4
-)sin (1)
sin (1) cos (#2) + (Os
Sin I
->
34
2
9. solve the equation for
0<x<2T
-5-13cosx
COS2 = -2 NOT POSSIBLE
-5= πT + 3 Cost - 3 costante
NO SOLUTION
10.
Solve the colution for x over 0 < x < 2 πT 2 sin²x - 3sinx+1=0
(-3) = √(-0) ²-a (2) (1)
25 in 2x - 35₁nx+1=0 → Sinx =
sinx
311
sin x 2 →→sinx=1 & sinx==2
4
s 414
1. I₁ ST → x = = = 50
T STL
Ex-2
& x <
11. Using
a double angle Identity to kind the exact
Cos x=-=// and II LALIT
4
valve
tan (2x)=
secx
Cos(x) sin(x)
(os(x)
CSC (2x)=
COS (2x)
sec (2x)
Cot (2x)
sin (2x):
2. verify the trig function: cosx (1 + +an²x)
Cos(x) (1 + tan² (x)) → (1 + +an² (x)) cos(x)
->
sin
= (1 + ((05 (2)) ³) cos (x) implify:
=
= sec (x) → TRUE
-
=
N3
15](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1fe4aef7-ed69-4d26-a412-f7dbb415fbf9%2F6ac6fe65-b497-46f2-b270-f022fd1d53b6%2Fj3fywid_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7.
Use a
exact value of
sin (
-reference angle
3
12
8
Use a half angle identity → sinl
TT
4
-)sin (1)
sin (1) cos (#2) + (Os
Sin I
->
34
2
9. solve the equation for
0<x<2T
-5-13cosx
COS2 = -2 NOT POSSIBLE
-5= πT + 3 Cost - 3 costante
NO SOLUTION
10.
Solve the colution for x over 0 < x < 2 πT 2 sin²x - 3sinx+1=0
(-3) = √(-0) ²-a (2) (1)
25 in 2x - 35₁nx+1=0 → Sinx =
sinx
311
sin x 2 →→sinx=1 & sinx==2
4
s 414
1. I₁ ST → x = = = 50
T STL
Ex-2
& x <
11. Using
a double angle Identity to kind the exact
Cos x=-=// and II LALIT
4
valve
tan (2x)=
secx
Cos(x) sin(x)
(os(x)
CSC (2x)=
COS (2x)
sec (2x)
Cot (2x)
sin (2x):
2. verify the trig function: cosx (1 + +an²x)
Cos(x) (1 + tan² (x)) → (1 + +an² (x)) cos(x)
->
sin
= (1 + ((05 (2)) ³) cos (x) implify:
=
= sec (x) → TRUE
-
=
N3
15
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