A double angle is used as the top chord of a given truss shown in figure 17.7. It is composed of 2- angles 225 x 100 x 12 mm. with short legs back to back. Thickness of gusset plate is 9 mm. Bracing is provided in the plane of the top chord every 2.2 m. Total length of the top chord is 8.8 m. but bracing between trusses is such that lateral support occurs only at the ends of the top chord. Neglect the contribution of roofing to lateral support. Use A 36 steel. K= 1.0, E, 200000 MPa. Compute the reduction factor due to local buckling of compression member. Compute the allowable compressive stress for the top chord. 2 3) Compute the maximum axial compressive force which the top chord can carry safely.
A double angle is used as the top chord of a given truss shown in figure 17.7. It is composed of 2- angles 225 x 100 x 12 mm. with short legs back to back. Thickness of gusset plate is 9 mm. Bracing is provided in the plane of the top chord every 2.2 m. Total length of the top chord is 8.8 m. but bracing between trusses is such that lateral support occurs only at the ends of the top chord. Neglect the contribution of roofing to lateral support. Use A 36 steel. K= 1.0, E, 200000 MPa. Compute the reduction factor due to local buckling of compression member. Compute the allowable compressive stress for the top chord. 2 3) Compute the maximum axial compressive force which the top chord can carry safely.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A double angle is used as the top chord of a given truss shown in figure 17.7. It is
composed of 2 - angles 225 x 100 x 12 mm. with short legs back to back. Thickness
of gusset plate is 9 mm. Bracing is provided in the plane of the top chord every 2.2 m.
Total length of the top chord is 8.8 m. but bracing between trusses is such that lateral
support occurs only at the ends of the top chord. Neglect the contribution of roofing
to lateral support. Use A 36 steel. K=1.0, E, 200000 MPa.
Compute the reduction factor due to local buckling of compression member.
2 Compute the allowable compressive stress for the top chord.
3)
Compute the maximum axial compressive force which the top chord can carry
safely.
Properties of 2 angles 2225 x 100 x 12 mm with short legs back to back
A 36 steel
CIVIL
A = 8064.5 mm²
rx = 26.67 mm
ry = 115.57 mm
F₁ 248 MPa
2.2
ENGINEERING STEEL DESIGN
8.8 m
2.2 2.2 2.2.
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