A dominant gene (W) produces wire-haired texture in dogs; its recessive allele (w) produces smooth hair. A group of heterozygous wire-haired individuals are crossed and their F1 progeny are then test-crossed. Determine the expected genotypic and phenotypic ratios among the test cross progeny:
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- More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handedMendelian Genetics (Monohybrid Cross) A. In dogs, a dominant gene (W) produces wire-haired texture. The recessive allele (w) produces smooth hair. A homozygous wire-haired male is mated to a homozygous female with smooth hair. What genotypes and phenotypes are expected i n their offsprings. Show the results of the crosses, the genotypic and phenotypic ratios. B. Normal pigmentation in humans result to a dominant allele (A), in which albinism results from the recessive allele (a). Two heterozygous individuals plan to have a child. What are the phenotypes of the parents? What is the chance that the child will be albino?Classical Mendelian Genetics, Incomplete Dominance, Codominance, and Multiple Alleles 1. Complete the table given below regarding the phenotype and genotype ratios in completely dominant traits. R and r represent the dominant and recessive allele, respectively. Type of Cross rrx rr RR x rr Rrx rr Rrx Rr Genotype Ratio Phenotype Ratio RR x Rr RR X RR *How would the genotype ratios be affected if the mode o inheritance in incomplete dominance? Codominance? 2. In dogs, barer trait is controlled by a dominant gene D and the silent trait by the recessive gene d. Normal tail is dependent on a dominant gene M and the screw m. Give the probable genotypes of the parents in the following crosses: Phenotype of parents Phenotypes of progeny Genotypes of parents Barker Barker Silent Silent normal screw normal normal a. silent normal x silent normal b. barker normal x silent normal 0 0 6 2 7 2 8 3 c. barker normal x silent screw 4 5 5 3 d. barker screw x silent normal 6 0 0 0 e. barker screw x…
- O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook AirTopic: Penetrance. Petal number is controlled by a single gene in merigonias. The gene has a completely dominant wild type allele F that makes a plant have five petals and a mutant recessive six petal allele(f). However the six petal trait is only 50% penetrant. You do the cross Ff x Ff. What fraction of the progeny do you have the 6 petals? what is the meaning for 50% penetrant.Drosohpila Punnet Square of Crosses. I need results of F1 & F2 generation using Punnett Squares for: Make Punnet Squares of the following crosses •Drosophila Female wildtype cross Male White-eye •Drosophila Male wildtype cross Female White-eye •Drosophila Female Wild Type cross Male Scarlet Eye •Drosophila Male Wild Type cross Female Scarlet Eye Also, Which allele is heterozygous and which is homozygous, & which is dominant and which is recessive?
- Incomplete dominanceIn Mendel's experiments, if the gene for tall (T) plants was incompletely dominant overthe gene for short (t) plants, what would be the result of crossing two Tt plants? Explain result.Now cross two of the F₁ offspring. Parent 1 Gametes F2 Offspring Parent 2 Gametes 24. What is the phenotypic ratio in the F2 generation? 25. In the dihybrid cross you have considered two traits at a time. Although the number of traits has increased by one, what has happened to the number of possible phenotypes of offspring produced in the F2 generation? ni llit asa2013 bhidydenom sih at Simons 1:11 sabrax gatameMendel's P1 Dihybrid Cross First parental (P1) generation WWGG wWgg Gametes WG Wg First filial (F1) generation Genotype Phenotype g bns es WwGg round and yellow- seeded plants Figure 1.3 Activity 4. SELF-CHECK 1. Based on the reșults of the dihybrid cross, can you tell which traits are dominant? Recessive? The P1 dihybrid cross is illustrated in Figure 1.3. Study it carefully. Capital letter W represents round pea seed which is dominant over wrinkled pea seed (w). Second parental (P2) generation (F1 self-pollinated) Ww Gg WwGg WG riWg WG of WG Gametes wG wG wg wg Second filial (F1) generation WG Wg wG to vitnsb Male wg Female WwGg 4 8 WWGg 2 wwgg 6 WwGg 10 14 WG WWGG 1 WWGG 3 Wg wG wWGg 5 WwGg 9 WwGg 13 WwGg 7 wwGg 11 wwGg 15 Wwgg wwGg 12 16 Wg Wwgg wwgg 2WwGg 4WwGg 2Wwgg Genotypic ratio 1 WWGG 2 WWG9 1WWgg 1wwGG 2wwGg 1wwgg
- Genetics 181 Rule of Incomplete Dominance When two different pure-breeding strains are crossed, and their offspring show a blending of phenotypes, then neither allele is dominant. This is easily recognized when the phenotype is somewhere between two extremes. Counting the parents, there are three phenotypes (black, white, grey) being expressed in these flowers instead of only two, and that third phenotype is intermediate between the other two. This heterozygous condition is called incomplete dominance. 1. On the chart you did earlier, which of the three hair types (wavy, curly, or straight) represents incomplete dominance-the blended heterozygous condition? 2. You cross a herd of red cattle with white cattle and all of the calves appear to be roan (reddish white). Is this an example of incomplete dominance? How do you know? 3. You cross a blue flowering pea plant with a white flowering pea plant and all of the offspring are blue flowered. Is this an example of incomplete dominance? How…parent genoty offspring genotypes. We can use this to figure out the probability of 1 How MANY HERITABLE TRAITS ARE USED IN DIHYBRID CROSS? 2. DIHYBRID CROSSES FOLLOW THE SAME RULES AS WHICH OTHER GENETIC DIAGRAM? Dunnet square S 3. How MANY OFFSPRING GENOTYPES ARE WORKED OUT IN A DIHYBRID CROSS? Emmatheteachie 2020 Dihybrid Crosses - Phenotypes LET'S CHECK IF YOU REMEMBER THE RULES FROM CREATING PUNNETT SQUARES! COMPLETE THE SENTENCES: Dominant alleles are represented with a letter. I'M THE BOS! Tt The capital letter is always written Each parent can only pass on allele for each gene. Recessive traits are only shown if both alleles are Now USE THE INFORMATION IN THE PICTURES BELOW TO WORK OUT THE PHENOTYPE FOR EACH GENOTYPE: Dominant traits Recessive traits Bubble fur (B) Spiky fur (b) Yellow body (M Pink body (y) BBYY = BbYy = Bbyy = bbYY= © Ermmotheleachie 2020. As we learned in this chapter, the white mutation ofDrosophila studied by Thomas Hunt Morgan isX-linked and recessive to wild type. When truebreeding white-eyed males carrying this mutationwere crossed with true-breeding purple-eyed females,all the F1 progeny had wild-type (red) eyes. When theF1 progeny were intercrossed, the F2 progeny emergedin the ratio 3/8 wild-type females: 1/4 white-eyedmales: 3/16 wild-type males: 1/8 purple-eyed females:1/16 purple-eyed males.a. Formulate a hypothesis to explain the inheritanceof these eye colors.b. Predict the F1 and F2 progeny if the parental crosswas reversed (that is, if the parental cross wasbetween true-breeding white-eyed females andtrue-breeding purple-eyed males).