A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 3 points with 99% confidence, assuming $ s = 12.2 $ based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required?- **Click the icon to view a partial table of critical values.**1. **A 99% confidence level requires ____ subjects.** (Round up to the nearest subject.)2. **A 90% confidence level requires ____ subjects.** (Round up to the nearest subject.)**How does the decrease in confidence affect the sample size required?**- **A.** Decreasing the confidence level increases the sample size needed.- **B.** Decreasing the confidence level decreases the sample size needed.- **C.** The sample size is the same for all levels of confidence.**[Click to select your answer(s)]**

Name: A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-
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Description: A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 3 points with 99% confidence, assuming $ s = 12.2 $ based on earlier studies? Suppose t

Sample size for 99% confidence level: It is given that the standard deviation is 12.2. Margin of error, E is 3. The confidence level is 99%. Therefore, α = 0.01. In this case, α/2=0.005, 1– α/2 = 0.995. The z-critical value for 99% confidence interval is 2.58 using the Excel formula “=NORM.S.INV (0.995)”. The required sample size is calculated as follows: n = (z× standard deviation /E)2 = ((2.58×12.2)/3)2 = 110.082 = 111 Thus, n=111 Sample size for 90% confidence level: It is given that the standard deviation is 12.2. Margin of error, E is 3. The confidence level is 90%. Therefore, α = 0.10. In this case, α/2=0.05, 1– α/2 = 0.95. The z-critical value for 90% confidence interval is 1.645 using the Excel formula “=NORM.S.INV (0.95)”. The required sample size is calculated as follows: n = (z× standard deviation /E)2 = ((1.645×12.2)/3)2 = 44.7516 = 45 Thus, n=45 As the confidence level decreases, the sample size also decreases. Correct answer is option (B).

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A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How marny subjects are needed to estimate the mean HDL. cholesterol within 3 points with 9% confidence assuming s = 12.2 based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required? Click the icon to view a partial table of critical values A 99% confidence level requires subjects (Round up to the nearest subject.) A 90% confidence level requires subjects (Round up to the nearest subject) How does the decrease in confidence affect the sample size required? O A. Decreasing the confidence level increases the sample size needed O B. Decreasing the confidence level decreases the sample size needed. O C. The sample size is the same for all levels of confidence

A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How marny subjects are needed to estimate the mean HDL. cholesterol within 3 points with 9% confidence assuming s = 12.2 based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required? Click the icon to view a partial table of critical values A 99% confidence level requires subjects (Round up to the nearest subject.) A 90% confidence level requires subjects (Round up to the nearest subject) How does the decrease in confidence affect the sample size required? O A. Decreasing the confidence level increases the sample size needed O B. Decreasing the confidence level decreases the sample size needed. O C. The sample size is the same for all levels of confidence

MATLAB: An Introduction with Applications

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ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

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A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 3 points with 99% confidence, assuming $ s = 12.2 $ based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required?

- **Click the icon to view a partial table of critical values.**

1. **A 99% confidence level requires ____ subjects.** (Round up to the nearest subject.)

2. **A 90% confidence level requires ____ subjects.** (Round up to the nearest subject.)

**How does the decrease in confidence affect the sample size required?**

- **A.** Decreasing the confidence level increases the sample size needed.
- **B.** Decreasing the confidence level decreases the sample size needed.
- **C.** The sample size is the same for all levels of confidence.

**[Click to select your answer(s)]**

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