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A diver initially moving horizontally with speed v dives off the edge of a vertical cliff and lands in the water a distance d from the base of the cliff. How far from the base of the cliff would the diver have landed if the diver initially had been moving horizontally with speed 2v?

A diver initially moving horizontally with speed v dives off the edge of a vertical cliff and lands in the water a distance d from the base of the cliff. How far from the base of the cliff would the diver have landed if the diver initially had been moving horizontally with speed 2v?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hello, I know the answer is 2d but I want to know how to get to that answer. Please help.

**Question:** A diver initially moving horizontally with speed \( v \) dives off the edge of a vertical cliff and lands in the water a distance \( d \) from the base of the cliff. How far from the base of the cliff would the diver have landed if the diver initially had been moving horizontally with speed \( 2v \)? **Options:** a. \( d \) b. \( 4d \) c. \( 2d \) d. \( \sqrt{2d} \) **Answer Explanation:** The problem involves projectile motion. The diver's horizontal distance from the base of the cliff is influenced by the horizontal component of velocity only. Doubling the horizontal velocity will, in the absence of air resistance, double the distance. Therefore, the answer is \(\mathbf{2d}\). The correct choice marked by the red cross is option **c. 2d**.
Transcribed Image Text:**Question:** A diver initially moving horizontally with speed \( v \) dives off the edge of a vertical cliff and lands in the water a distance \( d \) from the base of the cliff. How far from the base of the cliff would the diver have landed if the diver initially had been moving horizontally with speed \( 2v \)? **Options:** a. \( d \) b. \( 4d \) c. \( 2d \) d. \( \sqrt{2d} \) **Answer Explanation:** The problem involves projectile motion. The diver's horizontal distance from the base of the cliff is influenced by the horizontal component of velocity only. Doubling the horizontal velocity will, in the absence of air resistance, double the distance. Therefore, the answer is \(\mathbf{2d}\). The correct choice marked by the red cross is option **c. 2d**.
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