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A distillation column has a feed rate of 100 mol/hr of an equimolar mixture of three alcohols X, Y, and Z is separated giving out two output streams. The distillate has 2/3 X and no Z. The bottom stream contains no X. a.How many independent equations can be made based on the given conditions? b. How many unkown variables are needed to be solved? c. What is the mole fraction of Y in the bottom stream?

A distillation column has a feed rate of 100 mol/hr of an equimolar mixture of three alcohols X, Y, and Z is separated giving out two output streams. The distillate has 2/3 X and no Z. The bottom stream contains no X. a.How many independent equations can be made based on the given conditions? b. How many unkown variables are needed to be solved? c. What is the mole fraction of Y in the bottom stream?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A distillation column has a feed rate of 100 mol/hr of an equimolar mixture of three alcohols X, Y, and Z is separated giving out two output streams. The distillate has 2/3 X and no Z. The bottom stream contains no X. a.How many independent equations can be made based on the given conditions? b. How many unkown variables are needed to be solved? c. What is the mole fraction of Y in the bottom stream?
Transcribed Image Text:A distillation column has a feed rate of 100 mol/hr of an equimolar mixture of three alcohols X, Y, and Z is separated giving out two output streams. The distillate has 2/3 X and no Z. The bottom stream contains no X. a.How many independent equations can be made based on the given conditions? b. How many unkown variables are needed to be solved? c. What is the mole fraction of Y in the bottom stream?
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