A disc rolls straight on a flat floor without slipping. The magnitude of the angular velocity ω= 3.0 rad/s, the angular acceleration α=2.0 rad/s2. The radius of the disc is r=1.0 m

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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  1. A disc rolls straight on a flat floor without slipping. The magnitude of the angular velocity ω= 3.0 rad/s, the angular acceleration α=2.0 rad/s2. The radius of the disc is r=1.0 m. 



     

    b) Is the following statement true?

                    Point A shown above is the instant center of zero velocity of the disk at the moment.

     True

     False

**Rotational Motion of a Rolling Disc**

**Problem Statement:**
A disc rolls straight on a flat floor without slipping. The magnitude of the angular velocity \( \omega \) is \( 3.0 \, \text{rad/s} \), and the angular acceleration \( \alpha \) is \( 2.0 \, \text{rad/s}^2 \). The radius of the disc is \( r = 1.0 \, \text{m} \).

**Diagram Explanation:**
The accompanying diagram shows a disc rolling on a horizontal surface. Key elements in the diagram include:
- **G**: The center of the disc.
- **A**: The point of contact of the disc with the floor at any given instant.
- The radius of the disc with the labeled 'r'.
- The angular velocity \( \omega \) and angular acceleration \( \alpha \) are indicated by arrows indicating their directions of action.

The graphical representation indicates the rotational motion with angular velocity \( \omega \) and angular acceleration \( \alpha \) at the center of the disc (point G) while point A remains in contact with the floor.

**Concept Check:**
b) Is the following statement true?

**Statement:**
"Point A shown above is the instant center of zero velocity of the disk at the moment."

Options:
- True
- False

**Educational Explanation:**
In the context of rotational motion, the instant center of zero velocity is a point on a rigid body undergoing planar motion, which has zero velocity at a particular moment in time. For a rolling disc without slipping, this point lies at the point of contact with the floor, i.e., point A in the diagram, because this is the point where the tangential speed due to rotation exactly cancels out any translational speed resulting in a net velocity of zero.

**Conclusion:**
Therefore, the correct answer to whether point A is the instant center of zero velocity of the disk at the moment, is:
- **True**
Transcribed Image Text:**Rotational Motion of a Rolling Disc** **Problem Statement:** A disc rolls straight on a flat floor without slipping. The magnitude of the angular velocity \( \omega \) is \( 3.0 \, \text{rad/s} \), and the angular acceleration \( \alpha \) is \( 2.0 \, \text{rad/s}^2 \). The radius of the disc is \( r = 1.0 \, \text{m} \). **Diagram Explanation:** The accompanying diagram shows a disc rolling on a horizontal surface. Key elements in the diagram include: - **G**: The center of the disc. - **A**: The point of contact of the disc with the floor at any given instant. - The radius of the disc with the labeled 'r'. - The angular velocity \( \omega \) and angular acceleration \( \alpha \) are indicated by arrows indicating their directions of action. The graphical representation indicates the rotational motion with angular velocity \( \omega \) and angular acceleration \( \alpha \) at the center of the disc (point G) while point A remains in contact with the floor. **Concept Check:** b) Is the following statement true? **Statement:** "Point A shown above is the instant center of zero velocity of the disk at the moment." Options: - True - False **Educational Explanation:** In the context of rotational motion, the instant center of zero velocity is a point on a rigid body undergoing planar motion, which has zero velocity at a particular moment in time. For a rolling disc without slipping, this point lies at the point of contact with the floor, i.e., point A in the diagram, because this is the point where the tangential speed due to rotation exactly cancels out any translational speed resulting in a net velocity of zero. **Conclusion:** Therefore, the correct answer to whether point A is the instant center of zero velocity of the disk at the moment, is: - **True**
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