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A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by E- (0, 4nto The charges making up the dipole are +3 nC and -3 nC, and the dipole separation is 2 mm (as shown in Figure below). * (0, 0.04, 0)m * (0, 0.03, 0)m +3 nC -3 nC Q29 The change in potential energy when one moves along a path starting at location (0, 0.03, O) m and ending at location (0, 0.04, 0) m is given by the integral

A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by E- (0, 4nto The charges making up the dipole are +3 nC and -3 nC, and the dipole separation is 2 mm (as shown in Figure below). * (0, 0.04, 0)m * (0, 0.03, 0)m +3 nC -3 nC Q29 The change in potential energy when one moves along a path starting at location (0, 0.03, O) m and ending at location (0, 0.04, 0) m is given by the integral

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A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by E-( 4mc The charges making up the dipole are +3 nC and -3 nC, and the dipole separation is 2 mm (as shown in Figure below). * (0,0.04, 0)m X (0, 0.03, 0)m 32 +3 nC --3 nC Q29 The change in potential energy when one moves along a path starting at location (0, 0.03, O) m and ending at location (0, 0.04, 0) m is given by the integral O r0.04 24s dy Jo03 4xroy r0.04 24 dy Jo.03 O r0.03 Jo04 q dy Anay - Jo.04 ac r0.03 qs dy A very long wire carrying a conventional current of 3.5 A is straight in the positive x- direction except for a circular loop of radius 5.8 cm as shown in the Figure below. The positive y-direction is upwards and the positive z-direction is out of the page. 3.5 A 5.8 cm Q28 Calculate the approximate magnitude and the direction of the magnetic field vector at the center of the loop. O(0,0, -1.21e-5)T O (0, 0, +3.79e-5 )T O10,0, -5.00e-5)T O(0, 0, +2.85e-5 )T this is part of q29 Refer to text in Q29 again. Q30 The numerical value of the change in potential energy difference along a path starting at location (0, 0.03, 0)m and ending at location (0, 0.04, 0)m is O-13.2 V O+13.2 V O +26.3 V O-26.3 V
Transcribed Image Text:A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by E-( 4mc The charges making up the dipole are +3 nC and -3 nC, and the dipole separation is 2 mm (as shown in Figure below). * (0,0.04, 0)m X (0, 0.03, 0)m 32 +3 nC --3 nC Q29 The change in potential energy when one moves along a path starting at location (0, 0.03, O) m and ending at location (0, 0.04, 0) m is given by the integral O r0.04 24s dy Jo03 4xroy r0.04 24 dy Jo.03 O r0.03 Jo04 q dy Anay - Jo.04 ac r0.03 qs dy A very long wire carrying a conventional current of 3.5 A is straight in the positive x- direction except for a circular loop of radius 5.8 cm as shown in the Figure below. The positive y-direction is upwards and the positive z-direction is out of the page. 3.5 A 5.8 cm Q28 Calculate the approximate magnitude and the direction of the magnetic field vector at the center of the loop. O(0,0, -1.21e-5)T O (0, 0, +3.79e-5 )T O10,0, -5.00e-5)T O(0, 0, +2.85e-5 )T this is part of q29 Refer to text in Q29 again. Q30 The numerical value of the change in potential energy difference along a path starting at location (0, 0.03, 0)m and ending at location (0, 0.04, 0)m is O-13.2 V O+13.2 V O +26.3 V O-26.3 V
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