A dilute gas at a pressure of 2.0 atm and a volume of 2.0 L is taken through the following quasi-static steps.A. an isobaric expansion to a volume of 19.0 LB. an isochoric change to a pressure of 0.70 atmC. an isobaric compression to a volume of 2.0 LD. an isochoric change to a pressure of 2.0 atmShow these steps on a pV diagram.р (atm)p (atm)p (atm)p (atm)ADAD2.02.02.02.0DAВ0.700.700.700.70CBCBV (L)V (L)V (L)V (L)2.019.02.019.02.019.02.019.0Determine from your graph the net work done by the gas (in J).

Answered: Image /qna-images/answer/7896ca0d-0404-4ed1-928d-9fc6bef5f7b6.jpg

Answered: A dilute gas at a pressure of 2.0 atm…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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28. Water vapor is cooled in a closed, rigid tank from 440°C and 100 bar to a final temperature of 270°C. What is the final pressure, in bar? а. 45 с. 65 b. 55 d. 75
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3.2. Heat and Work 0.2 kg of argon (mon-atomic ideal gas, R = 0.208 kJ/kgK ), initially at 250K, are confined in an isochoric system of 0.15 m^3 volume, and 2.5 kg of xenon (mon-atomic ideal gas, R = 0.063 kJ/kgK ), initially at 420K, are confined in an isobaric piston-cylinder system at 1.8 bar. Both systems are brought into thermal contact and equilibrate their temperatures with no heat loss to the outside. What is the final temperatures, pressures and volumes of both gases, the work done by both systems, and the amount of heat transferred between the two systems and the total generation of entropy? (Sgen= ∫ Sgen dt ) and s=Cv =3/2R, Cp =5/2R
4. Saturated liquid at 300°C the internal energy (u) is A. 2563.6 kJ/kg B. 2345.4 kJ/kg C. 1332.7 kJ/kg D. 1230.9 kJ/kg
Handwritten solution required this is a basic thermodynamics question
T13 please help me with the answer and full solution
! Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine the hfg of refrigerant-134a at 20°F. Use data from the tables. The gas constant of refrigerant-134a is R= 0.01946 Btu/lbm.R. Consider Clapeyron-Clausius equation for calculations. The hfg of refrigerant-134a at 20°F is Btu/lbm.
2. An ideal gas (the weight is m kg) in an idealized piston-cylinder assembly undergoes a series of processes from state 1 to states 2, 3 and 4. Each state is at equilibrium. The gas can be modeled as a closed system. Ignore changes of KE and PE. The states are fixed by the following properties in the table: State 1 2 3 4 8 7 9 Note: State 1 to 2 is a constant-temperature process. State 2-3 is a constant-volume process. State 3-4 is a constant-temperature process. (a) Mark the states 1-4 and draw the three processes (1-2, 2-3, 3-4) on the following p-v diagram. p (bar) 4 5 3 1 2 0 p (bar) 1 3 1 6 3 v (m³/kg) 3 1 1 2 2 300K 600K T (K) 300 300 600 600 3 4 5 v (m³/kg) 6 7 8 (b) Use equations and simple texts to explain and answer the questions for the two processes (process 1-2, and process 2-3), respectively. (i) How does the internal energy change during each process: no change, increase or decrease (AU)? (ii) How does the enthalpy change during each process (AH)? (iii) Is the work…
At the pressure of P=0.1MPa, the saturation temperature of water is Tsat=100 ºC, the specific volume of the saturated liquid water is vf=0.001043 m3/kg, and the specific volume of the saturated vapor water is vg=1.6720 m3/kg. (2) Select the correct saturated liquid line and saturated vapor line ________
This question requires the use of the extracts from the tables of thermodynamic properties supplied. A system in equilibrium contains steam at a pressure of 15 bar and a temperature of 450 °C. What is the specific enthalpy of the steam? 3364 J/kg a. b. 3364 kJ/kg c. 2792 J/kg O d. 2792 MJ/kg K O e. 2792 kJ/kg

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