A diffraction pattern is produced on a screen 134 cm from a single slit, using monochromatic light of wavelength 530 nm. The distance from the center of the central maximum to the first-order maximum is 3.20 mm. Calculate the slit width. (Hint: Assume that the first-order maximum is halfway between the first- and second-order minima.)
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A diffraction pattern is produced on a screen 134 cm from a single slit, using monochromatic light of wavelength 530 nm. The distance from the center of the central maximum to the first-order maximum is 3.20 mm. Calculate the slit width. (Hint: Assume that the first-order maximum is halfway between the first- and second-order minima.)
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- A square diffraction grating of width 2.2 cm contains 6500 slits. At what angle does light with a wavelength of 690 nm produce the first order maximum? Answer in degrees, °.A single slit forms a diffraction pattern, with the first minimum at an angle of 30.0° from central maximum, when monochromatic light of 630-nm wavelength is used. The same slit, illuminated by a new monochromatic light source, produces a diffraction pattern with the third minimum at a 60.0° angle from the central maximum. What is the wavelength of this new light?Please help
- A monochromatic light of 658-nm wavelength shines on a single slit and forms a diffraction pattern with the first minimum at an angle of 41.0° from central maximum,. The same slit, illuminated by a new monochromatic light source, produces a diffraction pattern with the second minimum at a 57.0° angle from the central maximum. What is the wavelength of this new light in nanometers? Please give your answer with no decimal places.Light with wavelength λ passes through a narrow slit of the width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distance d from the middle of the central maximum. Show that λ, w, D and d are related by the expression dw = λD. Calculate D for λ = 421 nm, d = 0.2 cm and w = 0.8 mm.Monochromatic light of wavelength 622 nm is incident on a single-slit of width 0.321 mm. The diffraction pattern is observed on a screen 4.88 m from the slit. The intensity at the center of the central maximum is I_0. What is the distance (in mm) on the screen from the center of the central maximum to a point on the screen where the intensity has fallen to I_0/2?
- A diffraction pattern is produced on a screen 140 cm from a single slit, using monochromatic light of wavelength 500 nm. The distance from the center of the central maximum to the first-order maximum is 3.00 mm. Calculate the slit width. Hint: Assume that the first-order maximum is halfway between the first and second-order minima.Monochromatic light (wavelength = 455 nm) is incident perpendicularly on a single slit (width = 0.56 mm). A screen is placed parallel to the slit plane, and on it the distance between the two minima on either side of the central maximum is 2.1 mm. (a) What is the distance from the slit to the screen? (Hint: The angle to either minimum is small enough that sin ≈ tan 9.) (b) What is the distance on the screen between the first minimum and the third minimum on the same side of the central maximum? (a) Number 120 (b) Number i 1.8 Units Units cm mmIn a single-slit diffraction experiment, what must be the ratio of the slit width to the wavelength if the second diffraction minima are to occur at an angle of 37.0° from the center of the diffraction pattern on a viewing screen?
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