- A dielectric slab is slowly inserted between the plates of a parallel plate capacitor while the capacitor is connected to a battery. As it is being inserted: a. The capacitance and the charge on the plate increase but the potential difference between the plates remains the same b. The capacitance and the charge on the positive plate decrease but the potential difference between the plates remains the same c. The potential difference between the plates increases, the charge on the positive plate decreases, and the capacitance remains the same d. The capacitance, the potential difference between the plates, the charge on the positive plate all decrease

- A dielectric slab is slowly inserted between the plates of a parallel plate capacitor while the capacitor is connected to a battery. As it is being inserted: a. The capacitance and the charge on the plate increase but the potential difference between the plates remains the same b. The capacitance and the charge on the positive plate decrease but the potential difference between the plates remains the same c. The potential difference between the plates increases, the charge on the positive plate decreases, and the capacitance remains the same d. The capacitance, the potential difference between the plates, the charge on the positive plate all decrease

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Please walkthrough A parallel-plate capacitor is connected to a battery and has charge +Q0 and −Q0 on its plates. While the capacitor remains connected to the battery, the separation between the plates is doubled. Explain what will happen to the charge on the capacitor plates and why.
5. A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it is connected to a battery of voltage Vo, it has charge of magnitude Qo on its plates. While it is connected to the battery, the space between the plates is filled with a material of dielectric constant 3. After the dielectric is added, the magnitude of the charge on the plates and the new capacitance are: (Show all steps) [2 marks] 1/3 Qo, 1/3 Co b. Qo, 1/3 Co а. Qo, Co d. 3Qo, Co с. 3Qo, 3Co е.
If the charge on the plates of a capacitor as well as the potential difference between the plates change, the capacitance of that capacitor A. increases B. decreases C. does not change D. It cannot be determined from the information given.
Increasing the distance between the plates of an isolated charged capacitor has what effect? A) It increases the electric field between the plates. B) It decreases the energy stored in the capacitor. C) It increases the charge on the plates. D) It increases the voltage difference between the plates
I need the answer as soon as possible
Chapter 26 A parallel-plate capacitor has plates of area 0.2 m? and a separation of 0.9 cm. A battery charges the plates to a potential difference of 100 V and is then disconnected. A dielectric slab of thickness 9 mm and dielectric constant 2 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? (c) What is the free charge q before the slab is inserted? and (d) What is the free charge q after the slab is inserted? (e) What is the magnitude of the electric field in the space between the plates and dielectric before inserting the dielectric? (f) What is the magnitude of the electric field in the space between the plates and dielectric after inserting the dielectric? (g) With the slab in place, what is the potential difference across the plates?
THE PLATES OF A PARALLEL PLATE CAPACITOR ARE MAINTAINED WITH CONSTANT POTENTIAL BY A BATTERY AS THEY ARE PULLED APART. DURING THE PROCESS. WHAT WILL HAPPEN TO THE NUMBER OF CHARGES ON THE PLATES? A) IT WILL INCREASE. B) IT WILL DECREAST.. C) IT WILL REMAIN THE SAME. D) IT SUDDENLY DISAPPEARS.
The parallel plates of a capacitor have an area of 0.15 m2 and are separated by 1 mm in air. i) What is the capacitance? ii) If the distance is doubled, what would be the new capacitance? iii) How is the capacitance modified if a dielectric of K=2 is added between the plates?
1- chapter26-question43 Thee capacitance of a cylindrical capacitor can be increased by: Option1 Option2 Option3 Option4 Option5 increasing the decreasing the decreasing increasing radius of the radius of the inner both the radius only by decreasing the length both the cylindrical and increasing the outer cylindrical of the inner radius of the shell and cylinder and the length decreasing the length inner cylinder and the length radius of the outer cylindrical shell
Don't dielectric on me Consider an isolated capacitor with initial charge Q. Which of the following is TRUE when an uncharged dielectric is inserted between the plates? I Capacitor charge remains the same II Capacitance increases III Electric field between the plates increases A. I and II B. I and III С. П and III D. I, II, and III
What could be an option to vary the capacitance of a capacitor even though the plate areas and supply voltage are kept constant? by tilting one plate with reference to the other by changing the plate separation by breaking one plate by sliding one plate with reference to the other
A parallel-plate vacuum capacitor with capacitance C has plates with area A that are separated by distance d. What would be the capacitance if the area of one of the plates were increased to 2A while the other plate's area is reduced to A/2 (while keeping the separation between the plates the same)? O 20 O 3C/2 O C/2