A diagram of the collision between a moving cue ball and an initially stationary eight ball on a billiard table is given below. The collision of the billiard balls can be considered an isolated system. Eight ball V= 3.20 m/s m = 0.160 kg = 0.512 kg-m/s Cue ball V=4.00 m/s m = 0.180 kg p = 0.720 kg-m/s m = 0.180 kg 5. The maximum speed of the cue ball immediately after the collision is
A diagram of the collision between a moving cue ball and an initially stationary eight ball on a billiard table is given below. The collision of the billiard balls can be considered an isolated system. Eight ball V= 3.20 m/s m = 0.160 kg = 0.512 kg-m/s Cue ball V=4.00 m/s m = 0.180 kg p = 0.720 kg-m/s m = 0.180 kg 5. The maximum speed of the cue ball immediately after the collision is
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![A diagram of the collision between a moving cue ball and an initially stationary eight ball
on a billiard table is given below. The collision of the billiard balls can be considered
an isolated system.
Eight ball
V= 3.20 m/s
m = 0.160 kg
= 0.512 kg-m/s
Cue ball
V=4.00 m/s
m = 0.180 kg
p = 0.720 kg-m/s
m = 0.180 kg
5. The maximum speed of the cue ball immediately after the collision is
V 1.16 m/s
O 2.58 m/s
O 2.81 m/s
O 2.90 m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7aca29aa-52ed-41d2-9104-579ee0ccb08f%2F1c7c63bc-1d25-496c-ab9a-b9d51941580b%2Fv10gk4e_processed.png&w=3840&q=75)
Transcribed Image Text:A diagram of the collision between a moving cue ball and an initially stationary eight ball
on a billiard table is given below. The collision of the billiard balls can be considered
an isolated system.
Eight ball
V= 3.20 m/s
m = 0.160 kg
= 0.512 kg-m/s
Cue ball
V=4.00 m/s
m = 0.180 kg
p = 0.720 kg-m/s
m = 0.180 kg
5. The maximum speed of the cue ball immediately after the collision is
V 1.16 m/s
O 2.58 m/s
O 2.81 m/s
O 2.90 m/s
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