Homework Help is Here – Start Your Trial Now!
Math
Probability
(a) df = 4, df = 15, F = 5.39 O P-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (b) df = 4, df = 15, F = 1.85 ⒸP-value> 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (c) df = 4, df₂ = 15, F = 4.84 OP-value> 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (d) df = 3, df₂= 20, F = 14.47 O P-value > 0.100 X O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (e) df = 3, df = 20, F = 2.62 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (f) df₁ = 4, df₂ = 50, F = 3.29 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001

(a) df = 4, df = 15, F = 5.39 O P-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (b) df = 4, df = 15, F = 1.85 ⒸP-value> 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (c) df = 4, df₂ = 15, F = 4.84 OP-value> 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (d) df = 3, df₂= 20, F = 14.47 O P-value > 0.100 X O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (e) df = 3, df = 20, F = 2.62 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (f) df₁ = 4, df₂ = 50, F = 3.29 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
See similar textbooks
icon
Related questions
Question

please help me. a,c,d,e,f

Give as much information as you can about the P-value for an upper-tailed F test in each of the following situations. USE SALT (a) df = 4, df₂ = 15, F = 5.39 O P-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (b) df = 4, df₂ = 15, F = 1.85 ⒸP-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (c) df = 4, df = 15, F = 4.84 OP-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (d) df = 3, df₂= 20, F = 14.47 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (e) df = 3, df = 20, F = 2.62 OP-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (f) df = 4, df₂ = 50, F = 3.29 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001
Transcribed Image Text:Give as much information as you can about the P-value for an upper-tailed F test in each of the following situations. USE SALT (a) df = 4, df₂ = 15, F = 5.39 O P-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (b) df = 4, df₂ = 15, F = 1.85 ⒸP-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (c) df = 4, df = 15, F = 4.84 OP-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (d) df = 3, df₂= 20, F = 14.47 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (e) df = 3, df = 20, F = 2.62 OP-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (f) df = 4, df₂ = 50, F = 3.29 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001
Expert Solution
steps

Step by step

Solved in 6 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer