please help me. a,c,d,e,f Give as much information as you can about the P-value for an upper-tailed F test in each of the following situations.USE SALT(a) df = 4, df₂ = 15, F = 5.39OP-value > 0.100Ⓒ 0.050 < P-value < 0.100O 0.010 < P-value < 0.050O 0.001 < P-value < 0.010O P-value < 0.001(b) df = 4, df₂ = 15, F = 1.85ⒸP-value > 0.100O 0.050 < P-value < 0.100O 0.010 < P-value < 0.050O 0.001 < P-value < 0.010O P-value < 0.001(c) df = 4, df = 15, F = 4.84OP-value > 0.100Ⓒ 0.050 < P-value < 0.100O 0.010 < P-value < 0.050O 0.001 < P-value < 0.010OP-value < 0.001(d) df = 3, df₂= 20, F = 14.47O P-value > 0.100O 0.050 < P-value < 0.100O 0.010 < P-value < 0.050O 0.001 < P-value < 0.010O P-value < 0.001(e) df = 3, df = 20, F = 2.62OP-value > 0.100O 0.050 < P-value < 0.100O 0.010 < P-value < 0.050O 0.001 < P-value < 0.010O P-value < 0.001(f) df = 4, df₂ = 50, F = 3.29O P-value > 0.100O 0.050 < P-value < 0.100O 0.010 < P-value < 0.050O 0.001 < P-value < 0.010O P-value < 0.001

We can use R-programming to calculate p-values for F test statistic. In R, we use…

(a) df = 4, df = 15, F = 5.39 O P-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (b) df = 4, df = 15, F = 1.85 ⒸP-value> 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (c) df = 4, df₂ = 15, F = 4.84 OP-value> 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (d) df = 3, df₂= 20, F = 14.47 O P-value > 0.100 X O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (e) df = 3, df = 20, F = 2.62 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (f) df₁ = 4, df₂ = 50, F = 3.29 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001

(a) df = 4, df = 15, F = 5.39 O P-value > 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (b) df = 4, df = 15, F = 1.85 ⒸP-value> 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (c) df = 4, df₂ = 15, F = 4.84 OP-value> 0.100 Ⓒ 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 (d) df = 3, df₂= 20, F = 14.47 O P-value > 0.100 X O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (e) df = 3, df = 20, F = 2.62 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 OP-value < 0.001 (f) df₁ = 4, df₂ = 50, F = 3.29 O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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